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pogonyaev
3 years ago
14

How to go from a compound to a name and from a name to a compound?

Chemistry
1 answer:
Leno4ka [110]3 years ago
6 0
Convert between the chemical formula of an ionic compound and its name ... When naming ionic compounds, the cation retains the same name as the element.
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Who discovered the flame test
Genrish500 [490]

Answer:

Thomas Melvill

Explanation:

...

6 0
4 years ago
How would oxygen be represented in the formula equation for the reaction of methane and oxygen to yield carbon dioxide and water
Lera25 [3.4K]

Answer:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Explanation:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Methane + oxygen → carbon dioxide + Water.

The balanced equation above shows the combustion of methane, CH4 in oxygen, O2 to yield carbon dioxide, CO2 and steam, H2O.

The mole ratio of combustion are as follows:

1 mole of CH4 burns in 2 moles of oxygen to produce 1 mole of CO2 and 2 moles of H2O and a lot of heat.

6 0
3 years ago
How many moles of methane are in 7.31*10^25 molecules?
GrogVix [38]
<h3>Answer:</h3>

121 mol CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Organic</u>

  • Writing chemical compounds
  • Writing organic structures
  • Prefixes
  • Alkanes, Alkenes, Alkynes

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.31 × 10²⁵ molecules CH₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 7.31 \cdot 10^{25} \ molecules \ CH_4(\frac{1 \ mol \ CH_4}{6.022 \cdot 10^{23} \ molecules \ CH_4} ) = 121.388 \ mol \ CH_4<u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

121.388 mol CH₄ ≈ 121 mol CH₄

7 0
3 years ago
The half-life of thorium-227 is 18.72 days. How many days are required for three-fourths of a given amount to decay?
Pie
T½=18.72days
therefore t¾=18.72+½ of 18.72
we have 18.72+9.36=28.08days
7 0
3 years ago
Elemental iodine (I 2) is a solid at room temperature. What is the major attractive force that exists among different I 2 molecu
Ulleksa [173]

Explanation:

As I_{2} is a covalent compound because it is made up by the combination of two non-metal atoms. Atomic number of an iodine atom is 53 and it contains 7 valence electrons as it belongs to group 17 of the periodic table.

Therefore, sharing of electrons will take place when two iodine atoms chemically combine with each other leading to the formation of a covalent bonding.

Hence, weak forces like london dispersion forces will be present between a molecule of I_{2}.

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

thus, we can conclude that london dispersion force is the major attractive force that exists among different I_{2} molecules in the solid.

7 0
4 years ago
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