Answer:
first triangle (to left) b=8, second one c=17
Step-by-step explanation:
for the first triangle (one to the left) the hypotenuse is 9, so let's use the pythagorean formula.
A^2 + B^2 = C^2
^ ^ ^
^ ^ Hypotenuse
^ second side
first side
Substitute:
5^2 + b^2 = 9^2
SImplify:
25+b^2 = 81
Reduce:
b^2 = 64
Simplify:
b=8
In the second triangle, we are given 2 sides.
Let's do the same thing we did in the first one.
Givens:
A = 8
B = 15
Find:
C
Substitute:
8^2 + 15^2 = c^2
Simplify
64 + 225 = c^2
Reduce:
289 = c^2
Let's now square root both sides
square root of 289 is 17
so we are left with this:
c=17
Phew, you did it!
Hope this helped :))
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-2x+14y=148*3x+5y=256
(-2x+14y)/148=3x+5y=256/148
(-x+y)37/7=3x+5y=64/37
37*7(x+y)/37=(3x+5y)*37=64/37*37
7(x+y)=111x+185y=64
7x-111x=-7y-185y+64
104x=191y+64
x=191y+64/104