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kakasveta [241]
2 years ago
8

Solve the problem . (x – 2) = –14(x – 8) 1) x=0 2)x=--5 1/3 3)x=-3 1/5 4)x=3 1/5

Mathematics
1 answer:
Mrrafil [7]2 years ago
8 0

Answer:

x=38/5

Step-by-step explanation:

distribute

Add 2 to both sides of the equation

Simplify

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lukranit [14]
$5.36 hope this helps
8 0
2 years ago
In the alphabet, x comes before y. Use this fact to describe a method for remembering how to write ordered pairs.
Fofino [41]

Answer:

Step-by-step explanation:

so when remembering how to write ordered pairs, think of the monkey bars. you have to get there before you can climb up, x being walking to the monkey bars and y being climbing up them. Think of the steps to get to the monkey bars compared to the fact that x is before y. getting to the monkey bars comes before climbing them, is x (run) and climbing them would be y (rise), and not the other way around because like the question said; x comes before y.

I really hope this wasn't too confusing. I'm really sorry if it was!

Hope this helps! :)

3 0
3 years ago
Please solve it<br>I need to submit this by tomorrow ​
Brrunno [24]

Answer:

1

Step-by-step explanation:

(3^{n-1})\cdot(3^{1-n})\\\\=3^{n-1+1-n}\\\\\longrightarrow n-1+1-n=(n-n)+(-1+1)=0+0=0\\\\=3^{0}\\\\=1

7 0
3 years ago
Please help and leave explanation
chubhunter [2.5K]

Answer: x = 150°

Step-by-step explanation:

The tangent intersects the circle's radius at a 90° angle, so ∠OAC = ∠OBC = 90°.

AOBC is a quadrilateral and we know that sum of interior angles of quadrilateral equals to 360°.

Now,

∠OAC + ∠OBC + ∠AOB + ∠ACB = 360°

90° + 90° + x + 30° = 360°

210° + x = 360°

x = 360° - 210°

x = 150°

7 0
3 years ago
1. Find the function f (x) =ax2 + bx+ c whose graph contains the points (1, 2), (-2,-7), and (2, -3). Write the system of equati
IRISSAK [1]

Answer:

1. The function is -2x^2 + x + 3.

Step-by-step explanation:

1. The point at (1,2) gives the equation:

a * (1^2) + 1b + c = 2

a + b + c = 2

The point at (-2,-7) gives the equation:

a * (-2^2) + (-2b) + c = 7

4a - 2b + c = -7

The point at (2,-3) gives the equation:

a * (2^2) + 2b + c = -3

4a + 2b + c = -3

Hence, all three equations are:

a + b + c = 2  

4a - 2b + c = -7  

4a + 2b + c = -3

Now, subtract the second equation from the third equation to get:

(4a + 2b + c) - (4a - 2b + c) = -3 - (-7)

4a - 4a + 2b + 2b + c - c = -3 + 7

4b = 4

b = 1

Hence, let's now update our previous equations:

a + 1 + c = 2         =>         a + c = 1

4a - 2(1) + c = -7         =>         4a + c = -5

4a + 2(1) + c = -3         =>         4a + c = -5

This can be further whittled down into two equations:

a + c = 1

4a + c = -5

Hence, we can now subtract the first equation from the second to get:

(4a + c) - (a + c) = -5 - 1

4a - a + c - c = -6

3a = -6

a = -2

Therefore, c = 3 (a + c = 1, -2 + c = 1, c = 1 + 2, c = 3).

And the function is -2x^2 + x + 3.

Hope this helped!

4 0
3 years ago
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