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3 years ago

Please help me on #20 and #21 and I will help you back;)

Mathematics

1 answer:

nevsk [136]3 years ago

5 0

3x9 = 27
2x4 = 8
4x3 = 12

27+8 = 35
35+12 = 47
47-10 = 37

You have 37$ left to pay. You get your answer by multiplying the amount of dinners or meals by the money, and add them all together and subtract the 10$ coupon.

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Plsss help !!

Gennadij [26K]

Answer:

carnation $2.50; rose $3.00

Step-by-step explanation:

Let c = price of 1 carnation.

Let r = price of 1 rose.

3c + 5r = 22.5

3c + 2r = 13.50

Subtract the se3cond equation from the first equation.

3r = 9

r = 3

Now substitute r = 3 in the first equation and solve for c.

3c + 5r = 22.5

3c + 5(3) = 22.5

3c = 7.5

c = 2.5

Answer: carnation $2.50; rose $3.00

5 0

3 years ago

If the length of AC equals 30, what is the length of the midsegment DE? A) 10 B) 15 C) 20 D) 25

Serhud [2]

Answer:

Step-by-step explanation:

3 0

4 years ago

Write an algebraic rule to describe the translation c (5,-4) c'(-2,1)

Sauron [17]

We can solve this by using the formula:
(x, y) (x + a, y + b) = (5,-4) (-2,1)

So, plugging in the values and solving for a and b,
5 + a = -2
a = -8

-4 + b = 1
b = 5

Therefore, the translation is
(x,y) (x - 8, y +5)

5 0

3 years ago

A store sells four printers for every five computers. The store sells 40 computers on Saturday. How many printers did it sell on

aleksley [76]

32 printers were sold:
P:C
4:5
_:40
40/5=8
4x8=32

3 0

3 years ago

1. Consider the data set 1,2,3,4,5,6,7,8,9.

ivanzaharov [21]

Answer: a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

Since we have given that

1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

$\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5$

Median = $(\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5$

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

$\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15$

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

5 0

3 years ago