Answer:
Identify the location of the college stand in advance.
Explanation:
One way to save time and get to the colleges that you are most interested in at a college fair is to find out in advance the information about the fair, the colleges that are participating and from that pick the more interesting ones and identify the location of their stands. Like that when you arrive to the fair you can go directly to them and find them easily which will save you a lot of time as you won't be walking around the whole place to find them.
Answer:
#include <iostream>
using namespace std;
int * reverse(int a[],int n)//function to reverse the array.
{
int i;
for(i=0;i<n/2;i++)
{
int temp=a[i];
a[i]=a[n-i-1];
a[n-i-1]=temp;
}
return a;//return pointer to the array.
}
int main() {
int array[50],* arr,N;//declaring three variables.
cin>>N;//taking input of size..
if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..
return 0;
for(int i=0;i<N;i++)
{
cin>>array[i];//prompting array elements..
}
arr=reverse(array,N);//function call.
for(int i=0;i<N;i++)
cout<<arr[i]<<endl;//printing reversed array..
cout<<endl;
return 0;
}
Output:-
5
4 5 6 7 8
8
7
6
5
4
Explanation:
I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.
Define variables
left is l
right is r
Ask input
left or right
Ask input value
Equate l or r to the input value
Show ladder with steps equal to input value and in the side of input variable
The program is an illustration of loops.
Loops are used to perform repetitive and iterative operations.
The program in C++ where comments are used to explain each line is as follows:
#include <iostream>
using namespace std;
int main(){
//This declares and initializes all variables
string star = "*", blank = " ", temp;
//The following iteration is repeated 8 times
for (int i = 1; i <= 8; i++) {
//The following iteration is repeated 8 times
for (int j = 1; j <= 8; j++) {
//This prints stars
if (j % 2 != 0) {
cout << star;
}
//This prints blanks
else if (j % 2 == 0) {
cout << blank;
}
}
//This swaps the stars and the blanks
temp = star;
star = blank;
blank = temp;
//This prints a new line
cout << endl;
}
}
Read more about similar programs at:
brainly.com/question/16240864
The answer seems to be polymerization.
