1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pani-rosa [81]
3 years ago
12

In Salem, 4 of the 10 radio stations play classical music.

Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

40% or 4/10 (assuming you just turned on the radio)

Step-by-step explanation:

If you just turned on the radio, it would be 4/10. If you changed from a channel that wasn't playing classical music then it would be 4/9. If you changed from a channel that was playing classical music then it would be 3/9.

You might be interested in
Using the property of exponents, what do you need to multiply 10^-2 by to get 10^-4?
r-ruslan [8.4K]

Answer:

We conclude that using the property of exponents, we need to multiply 10² to get 10⁴. Step-by-step explanation: Let 'x' be the number we need to multiply 10² by to get 10⁴. Therefore, we conclude that using the property of exponents, we need to multiply 10² to get 10⁴.

8 0
3 years ago
I need help does anyone know the slope intercept for this one?
Paraphin [41]

Answer:

(0,2)

Step-by-step explanation:

The slope-intercept (aka y-intercept) is where the line crosses the y-axis. And the slope-intercept is at (0,2)

Hope this helped!

Have a supercalifragilisticexpialidocious day!

7 0
3 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
Keith_Richards [23]
They used more cleaner in 2012 because the green line is higher in the year 2012 than it is in 2015.
6 0
3 years ago
Read 2 more answers
Anthony is going to invest in an account paying an interest rate of 2%
melomori [17]

Answer:

12283.01

Step-by-step explanation:

5 0
3 years ago
Other questions:
  • I need help please. Quick.
    14·2 answers
  • -3a + 4 ≥ -16<br><br> Solve, and show your work.
    12·2 answers
  • 21yz over 49xyz, what is the answer
    9·1 answer
  • What would the coordinates of the points be now ?
    5·1 answer
  • A finite population consists of four elements: 6, 1, 5, 3. (a) how many different samples of size n = 2 can be selected from thi
    9·1 answer
  • Write each number in expanded from 3,272
    12·2 answers
  • Please help me?!!!!!!
    9·2 answers
  • What is the exponent for the expression 6 × 6 × 6 × 6 × 6?
    10·1 answer
  • HELP I need this for a quiz the screenshot is there
    13·1 answer
  • Chang wants to attend a two-year university with an annual tuition of $3,250. He has $2,000 in savings and earned a work-study f
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!