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andre [41]
2 years ago
13

Find the area of the trapezoid by composition of rectangle and triangles. A) 30 units2 B) 38 units2 C) 42 units2 D) 54 units2

Mathematics
1 answer:
Brrunno [24]2 years ago
3 0

Answer:

Option C is correct.

The total area of the trapezoid = 42 units²

Step-by-step explanation:

After a little research online, the image missing from the question was obtained and is attached to the solution of this question.

In the trapezoid given, there are two triangles and a rectangle.

Area of rectangle = length × breadth

Length = 6 units

Breadth = 5 units

Area of the rectangle = 6 × 5 = 30 units²

Area of a triangle = ½ × Base × Height

Base = 2 units

Height = 6 units

Area of each of the exactly similar triangles = (1/2) × 2 × 6 = 6 units²

Area of the two similar triangles = 2 × 6 = 12 units²

Total Area of the trapezoid = (Area of rectangle) + (Area of the two triangles)

= 30 + 12 = 42 units²

Hope this Helps!!!

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Solve for x. Round your answer to 2 decimal places.<br> A. 8<br> B. 13.86<br> C. 18.48<br> D. 32
weqwewe [10]

Answer:

D) 32

Step-by-step explanation:

sin∠30=16/x first calculate sin∠30

1/2=16/x next cross multiply

x=32

Have a good day :)

3 0
2 years ago
Please help out !!!!
evablogger [386]

Answer:

x  = 8

Step-by-step explanation:

you have similar triangles here

so     2 is to 4  as  4 is to x

2/4 =  4/x

x = 8

8 0
3 years ago
Help! Thanks!!!!!!!!!
san4es73 [151]

1)

∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰

AB = 370 m

AC = 510 m

To find BC we can use cosine law.

a² = b² + c² -2bc*cos A

|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)

|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =

|BC| ≈ 553 m


2)

To find ∠ACB, we are going to use law of sine.

sin(∠BAC)/|BC| = sin(∠ACB)/|AB|

sin(76⁰)/553 m = sin(∠ACB)/370 m

sin(∠ACB)=(370*sin(76⁰))/553 =0.6492

∠ACB = 40.48⁰≈ 40⁰


3)

∠BAC = 76⁰

∠ACB = 40⁰

∠CBA = 180-(76+40) = 64⁰


Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰


4)

Shortest distance from A to BC is height (h) from A to BC.


We know that area of the triangle

A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).

Also, area the same triangle

A= (1/2)|BC|*h = (1/2)*553*h.


So, we can write

(1/2)*370*510*sin(76⁰) =(1/2)*553*h

370*510*sin(76⁰) =553*h

h= 370*510*sin(76⁰) / 553= 331 m

h=331 m


4 0
3 years ago
Sin^2(alpha) + cos^2(alpha)=? Fast plz sir is asking me rn lol
Crazy boy [7]

Answer:

the answer is 1

hope it helps

4 0
3 years ago
You and your family took a trip over track out that was 1.5 hours away. Which two trips could your family have taken?
dusya [7]

Answer:

i think a

Step-by-step explanation:

7 0
3 years ago
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