The loan amount is given as $76521
We first have to calculate the total amount of tuition
6970 x 4 + 11320 x 4
= 73160
<h3>a. How to solve for the new loan amount</h3>
= 73160 x (1 + 0.00375)¹²
= 76520.95
Hence the new loan amount after agrace period of 1 year = $76521
b. PV = $76521
i =
= 0.00375
t = 10 years
pmt = 793. 05
The monthly payment is $793. 05.
In ten years the total payment is 793.05 x 10 x 12
= 95166
Difference = 95166 - 76521
= $18645
In ten years her ,monthly payment on the loan would be $18645.
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Area=hxw
h=a/w
h=120/10
12=120/10
h=12
4t + 2 < 8t - (6t - 10)
4t + 2 < 8t - 6t + 10
4t + 2 < 2t + 10
4t - 2t < 10 - 2
2t < 8
t < 8/2
t < 4
Answer:
Length of the side be=11.9cm
Be=14sin58
Nvm=14 times 0.8480
Bc=11.9 cm
Step-by-step explanation:
, and . Subtract this from the numerator and you get a remainder of
, and . Subtract this from the previous remainder and you get a new remainder of
, and . Subtract this from the previous remainder and you get a new one of
, and . Subtract this from the previous remainder and you get a new one of
doesn't divide 120, so we're done, and putting everything together we've shown that