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liubo4ka [24]
3 years ago
14

Can I get an answer?

Mathematics
2 answers:
Reil [10]3 years ago
5 0

coordinate of B= (2+3,0) = (5,0)

by pythagoras' theorem,

height of triangle^2 + half length of AB^2 = AC^2

height of triangle^2 = 3^2-1.5^2

height of triangle ^2= 6.75

height of triangle= √6.75

coordinates of C= (1.5,√6.75)

chubhunter [2.5K]3 years ago
5 0

Answer:

B:  (5,0)

C: (3.5 , 3√3/2)

Step-by-step explanation:

ΔABC: equilateral triangle  CA=AB=BC=3

B: (2+3,0) i.e. (5,0)

AD=3/2=1.5

CD²=CA²-AD2 = 9 - 9/4 = 27/4      CD = 3√3 / 2

C: (2 + 3/2, 0 + 3√3/2)  i.e.  (3.5 , 3√3/2)

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4 0
3 years ago
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How do i solve this?
n200080 [17]
The polynomial is not factorable, so use the quadratic formula.

y^2 + 8y + 19 = 0

x = (-b +- sqrt(b^2 - 4ac))/(2a)

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x = (-8 +- sqrt(64 - 76))/2

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If you have not learned imaginary/complex numbers, then the answer is "No solution" since there is no real number solution.

If you have learned imaginary/complex numbers, then we'll continue.

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5 0
4 years ago
rico wants to buy a battery operated toy car which caused 580 7.50 he has already save one 50.00 points his ninong give him 200
myrzilka [38]

Answer:

19 days

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1 - Make an equation with the variables provided.

150 + 200 + 12.50x = 587.50

2 - Simplify both sides.

350 + 12.50x = 587.50

3 - Subtract 350 from both sides.

12.50x = 237.50

4 - Divide by 12.50 to find your x variable.

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3 0
2 years ago
Gavin has $7,500 to invest. He is considering two investment options. Option A pays 4% simple interest. Option B pays 3.15% inte
Leviafan [203]

Solution:

Principal =P= $ 7,500

Option A→(Simple interest)

Rate of interest= R=4%

Time(T_{1})=4 years

Time(T_{2})=6 years

Amount= Principal + Interest(Simple or compound interest)

Formula for Simple interest

S.I=\frac{P\times R\times T}{100}

S.I_{1}=\frac{7500 *4*4}{100}=1200\\\\ S.I_{2}=\frac{7500 *4*6}{100}=1800

Total amount after 4 years when interest is simple= 7500 +1200= $ 8700

Total amount after 6 years  when interest is simple= 7500 +1800= $ 9300

Option B

Formula for amount(A) when interest is 3.15% compounded annually.

A=P*(1+\frac{R}{100})^t

A_{4}=7500*(1+\frac{3.15}{100})^4\\\\ A_{4}=7500*(\frac{103.15}{100})^4\\\\ A_{4}=7500*(1.0315)^4\\\\ A_{4}=7500*1.1320\\\\ A_{4}=8490.60

A_{6}=7500*(1+\frac{3.15}{100})^6\\\\ A_{6}=7500*(\frac{103.15}{100})^6\\\\ A_{6}=7500*(1.0315)^6\\\\ A_{6}=7500*1.2045\\\\ A_{6}=9033.9286

Total amount after 4 years when interest is compounded annually=$ 8491 (approx)

Total amount after 6 years  when interest is compounded annually=$ 9034(approx)

4 0
3 years ago
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FrozenT [24]

Answer:

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