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3 years ago

Evaluate sin^2 θ for θ = 45°

Mathematics

1 answer:

NISA [10]3 years ago

5 0

Answer:

$\frac{1}{2}$

Step-by-step explanation:

sin45° = $\frac{1}{\sqrt{2} }$ ← exact value , then

sin²45° = $\frac{1}{\sqrt{2} }$ × $\frac{1}{\sqrt{2} }$ = $\frac{1}{2}$

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Find the radius of a circle with circumference of 45.84 meters. Use 3.14

alukav5142 [94]

Answer:

3.8 meters

Step-by-step explanation:

In order to find the circumference for a circle, we use the formula π(radius)²

The circumference give is 45.84 and the π given is 3.14

All we have to do is to just substitute them.

45.84 = 3.14(radius)²

45.84 / 3.14 = radius²

14.6 = radius²

radius = √14.6

radius = 3.82 ≅ 3.8

5 0

3 years ago

Read 2 more answers

Kelly bought a new car for $20,000. The car depreciates at a rate of 10% per year.

Vlad1618 [11]

Answer:

Use the formula.

P=P'(1-R/100)^T

where,

P=final rate

P'=initial rate

R=Rate of Depreciation

T=Time.

3 0

3 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

3 years ago

Can I please have help

Dima020 [189]

Answer:

15a+12ac+6ab

Step-by-step explanation:

3a(5 + 4c + 2b)

5*3a = 15a

4c*3a = 12ac

2b*3a = 6ab

6 0

3 years ago

Read 2 more answers

Geometry picture added

Nikitich [7]

X and Z equal 72
Y equals 108.

This is because y and 108° are vertex angles meaning they are both equal to each other. X is 72 because it’s form a supplementary angle with 108°. So what I did to find x is I subtracted 108 from 180 to get 72°. Then I know x and z are vertex angles meaning that z is also equal to 72°

5 0

3 years ago