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Shalnov [3]
2 years ago
6

N:2 = 15/5 solve it for n​

Mathematics
2 answers:
telo118 [61]2 years ago
5 0

Step-by-step explanation:

N:2 = 15:5

N\2 = 15\ 5

Now cross multiply,

5N = 30

N = 6

Readme [11.4K]2 years ago
3 0

Answer:

<h2><u><em>n = 6</em></u></h2>

Step-by-step explanation:

N:2 = 15/5 solve it for n

n : 2 = 15 : 5

n = 2 * 15 : 5

n = 30 : 5

n = 6

---------------------

check

6 : 2 = 15 : 5

3 = 3

the answer is good

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Alex787 [66]

mmmhmmm dont really know why ur telling us dis




4 0
3 years ago
A woman passed gas silently. I said "it stinks", and she said "I apologize. Excuse me". Why did she say both of those things?
Vikki [24]
She says “I apologise” because she feels bad that she made a bad smell and she says “excuse me” because she wants you to accept her apology
8 0
2 years ago
Using the circle below, determine the coordinates of the center and the length of the radius.
iogann1982 [59]

Answer:

Center (-2, 1), Radius 3

What is the distance from the midpoint of the circle to a point on the circle? It is 3 and not 9.

7 0
3 years ago
M is the midpoint of AB.<br> AM = = 4x - 8<br> MB =<br> 5x-3/3<br> Find x and AB
marusya05 [52]
X=-7 AB=-72

steps

since m is a midpoint, AM and MB are congruent so you set the two equations equal to each other, 4x-9=5x-3/3( is this a typo? bc 3/3 is 1)
subtract 4x from both sides m, -8=x-1
add 1 to both sides
x=-7

then plug -7 in for x 4(-7)-8=-36
since the two segments are congruent u do -36 x 2= -72
7 0
3 years ago
With full explanation from the internet like before<br> 3x2-6x+5=0
Elodia [21]

Answer:

\sf x=1+i\sqrt{\dfrac{2}{3}}   \ \quad and  \quad \:x=1-i\sqrt{\dfrac{2}{3}}

Explanation:

<u>Given Expression</u>:

  • 3x² - 6x + 5 = 0

Use the Quadratic Formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \  \ when   \ \  ax^2 + bx + c = 0

<u>insert coefficients</u>

\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}

\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}

\Longrightarrow \sf x =1 \pm   i\dfrac{\sqrt{6} }{3}

\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}},  \quad 1-i\sqrt{\dfrac{2}{3}}

6 0
2 years ago
Read 2 more answers
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