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Jlenok [28]
2 years ago
7

Marcela is registering for her college classes, which cost $105 per unit. How many units can she take to have a maximum cost of

$1,365?
Mathematics
2 answers:
vlabodo [156]2 years ago
7 0

Marcela can use 13 units.

OverLord2011 [107]2 years ago
6 0

Answer:

Marcela can take up to 13 units.  

Step-by-step explanation:

In order to find the number of units that Marcela can take for her college classes, we can set up an inequality and solve for the variable.  Since each unit costs $105, we can say that 105u ≤ 1365 where u = the number of units.  The number of units multiplied by the cost per unit, must be less than or equal to $1,365.  In order to solve for 'u', we can use inverse (opposite) operations and get rid of the coefficient by dividing both sides of the inequality by 105.  1365÷105 = 13.  So, the number of units that Marcela can take must be less than or equal to 13 units.  

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There are 4 cookies if there is 1/4 of a cookie in each bag how many bags will there be
Darya [45]

Answer:

there will be 16 bags

Step-by-step explanation:

3 0
3 years ago
Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0
2 years ago
The estimated product of 20.7 and 9.18, after rounding both factors to the nearest whole number,
lesya692 [45]

Answer:

20.7 --> 21

9.18 --> 9

21x9 is 189, thus the estimated product is 189.

Let me know if this helps!

7 0
2 years ago
4(4b-8)-3/8<br> Please help i have no idea what to do
Ksivusya [100]

Answer:

4(4b - 8) -  \frac{3}{8}  \\ 16b - 32 -  \frac{3}{4}  \\ \frac{64b - 128 - 3}{8}  \\  \frac{64b - 131}{8}

hope this will help you

7 0
1 year ago
What is 9 times -11 + 17 times 11 in factored form
Rama09 [41]

Answer:

88

Step-by-step explanation:

(17 * 11 = 187) + (9 * -11 = -99)

187 - 99 = 88

7 0
3 years ago
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