Given the data from the question, reaction 2 is 2.83 times faster compared to reaction 1
<h3>Data obtained from the question</h3>
- Molarity of reaction 1 (R₁) = 0.180 mol/L
- Molarity of reaction 2 (R₂) = 0.510 mol/L
- Comparison =?
<h3>How to determine the comparison of reaction 2 to reaction 1</h3>
We can determine how many times faster is reaction 2 to reaction by doing the following:
R₂ / R₁ = 0.510 / 0.180
R₂ / R₁ = 2.83
Cross multiply
R₂ = 2.83 × R₁
From the above illustration, we can see that reaction 2 is 2.83 times faster than reaction 1
Learn more about Graham's law of diffusion:
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The answer to this question is d
Answer:
102
Step-by-step explanation:
2(3)³ + 3(6-2)2
2 (27) + 3(4)2
54 + 48
102
Answer:
5x^2 + 20x = 5x(x + 4)
Step-by-step explanation:
Here, we want to factorize;
5x^2 + 20x
To do this, we start by writing the common factors
The common actor that we can see which is in the form of the gcf of both is 5x
Thus, the factorization will be;
5x^2 + 20x = 5x( x + 4)
Answer:
-8x-6 or -8x+-6.
Step-by-step explanation:
