All organic molecules must have carbon and hydrogen so it would be choice A
Answer:
2.5 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have two different values of V and P:
<em>P₁V₁ = P₂V₂
</em>
P₁ = 5.0 atm, V₁ = 3.5 L.
P₂ = 7.0 atm, V₂ = ??? L.
<em>∴ V₂ = P₁V₁/P₂ </em>= (5.0 atm)(3.5 L)/(7.0 atm) = <em>2.5 L.
</em>
Answer:
Option NH 3 is the correct answer.
Explanation:
A molecule which has hydrogen bonding will have the highest boiling point. So, out of the given options only NH 3 will have hydrogen bonding.
Whereas in CHCI 3 there will be dipole-dipole interactions and no hydrogen bonding within the molecule.
In OF 2 and C 6H 6, there will be dipole-dipole interaction in both the molecules.
Thus, we can conclude that NH 3 will have the highest boiling point.
Answer:
A)It has too many neutrons
Explanation:
Electrons are emitted from the nucleus when a neutron is converted to a proton, an electron and a neutrino. This process is popularly known as beta emission. It reduces the neutron-proton ratio of a nuclide. The neutrino is a particle of zero mass and zero charge that carries off the excess energy and balances spins.
The loss of an electron from the nucleus occurs when there are too many neutrons in the nucleus. The process of beta emission usually reduces the number of neutrons in an atom thereby decreasing the neutron-proton ratio.
Answer:
Chloroform is expected to boil at 333 K (60 
).
Explanation:
For liquid-vapor equilibrium at 1 atm, 
= 0.
We know, 
, where T is temperature in kelvin scale.
Here both 
and 
are corresponding to vaporization process therefore T represents boiling point of chloroform.
So, ![0=(31.4\times 10^{3}\frac{J}{mol})-[T\times (94.2\frac{J}{mol.K})]](https://tex.z-dn.net/?f=0%3D%2831.4%5Ctimes%2010%5E%7B3%7D%5Cfrac%7BJ%7D%7Bmol%7D%29-%5BT%5Ctimes%20%2894.2%5Cfrac%7BJ%7D%7Bmol.K%7D%29%5D)
or, T = 333 K
So, at 333 K (60 ) , chloroform is expected to boil.
