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Ksivusya [100]
2 years ago
5

In the titration of acetic acid, CH3COOH, a 0.20 M solution of NaOH is used. A volume of 15.00 mL of CH3COOH solution is

Chemistry
1 answer:
yan [13]2 years ago
6 0

Answer:

naci

Explanation:

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When does phenolphthalein turn pink?
Gelneren [198K]
Phenolphthalein<span> is often used as an indicator in acid–base titrations. For this application, it </span>turns<span> colorless in acidic solutions and </span>pink<span> in basic solutions. </span>Phenolphthalein<span> is slightly soluble in water and usually is dissolved in alcohols for use in experiments.

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7 0
3 years ago
Read 2 more answers
Analyzing a specific reaction Consider the following reaction: 2Mg+O2→2MgO,rate=k[Mg][O2]2 Part A What is the overall reaction o
stepladder [879]

Answer:

3

Explanation:

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

Thus,

For the reaction:-

2Mg+O₂→2MgO

Rate  = k[Mg][O₂]²

Order w.r.t. Mg = 1

Order w.r.t. O₂ = 2

<u>So, order of the overall reaction = 1 + 2 = 3</u>

7 0
3 years ago
Write a chemical equation for Ba(OH )2 (aq) showing how it is an acid or a base according to the Arrhenius definition.
Marina86 [1]
Balanced chemical reaction: Ba(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻(aq).
According <span>to the Arrhenius definition barium hydroxide is base.
According this theory a</span>cids are substances which produce hydrogen ions in water solution, bases are substances which produce hydroxide ions in solution. Acids and bases when react (neutralisation) produce salt and water.
5 0
2 years ago
4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.
Elodia [21]

Answer:

Y=48.6\%

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

2Cu+O_2\rightarrow 2CuO

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO}  =0.078gCuO

Therefore, the percent yield is:

Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%

Best regards.

6 0
3 years ago
I am on the 2th period and belong to the same group as silicon who am I ?
Rus_ich [418]
Rubber it is basically the same thing
4 0
2 years ago
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