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Shkiper50 [21]
2 years ago
9

I need help with this question

Mathematics
1 answer:
AlexFokin [52]2 years ago
3 0
A
Find the two intersections of the lines. The value of x of the intersections will satisfy the system of equations.
Brainliest pls!
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4x(x-25)=0 how to solve the quadratic equations using any of the four methods?​
butalik [34]

Answer:

x=25 or x=0

Step-by-step explanation:

4x(x−25)=0

Step 1: Simplify both sides of the equation.

4x2−100x=0

For this equation: a=4, b=-100, c=0

4x2+−100x+0=0

Step 2: Use quadratic formula with a=4, b=-100, c=0.

x=−b±√b2−4ac over 2a

x=−(−100)±√(−100)2−4(4)(0) over 2(4)

x=100±√10000 over 8

x=25 or x=0

7 0
3 years ago
Help please PLEASE IM FREAKING SERIOUS IF I DONT FINISH IT BY 9 IM DEAD ILL GIVE 50 POINTS HELP PLEASE IM ACTUA;LY FRICKIN SERRI
yuradex [85]

Answer:

1/4 i think

Step-by-step explanation:

hope this helps

if i was right pls mark brainliest

6 0
2 years ago
in your own words explain the place value relationship when the same two digits are next to each other in a multi digit number
zavuch27 [327]
I'll use 44.  
This number broken down means 4 in the 10's place and 4 in the ones place
 4(10)+4(1)= 40+4=44
4 0
3 years ago
Explain the relationship between the two 5's in the number 455.721
Pie
Well for this one just make it 455 its 55 so tens and ones colloum 
3 0
3 years ago
You and your friend are playing a game. The two of you will continue to toss a coin until the sequence HH or TH shows up. If HH
miskamm [114]

Answer:

The probability of friend A winning with HH = 1/4.

Step-by-step explanation:

The probability of an event, A is P(A) given by the relationship;

P(A) = (The number of required outcome)/(The number of possible outcomes)

The parameters given are;

The condition of friend A winning = Coin toss sequence HH shows up

The condition of friend B winning = Coin toss sequence TH shows up

The number of possible outcomes = TT, TH, HH, HT = 4

(TH and HT are taken as different for the game to be fair)

The number of required outcome = HH = 1

Therefore;

The probability of friend A winning with HH = 1/4.

5 0
3 years ago
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