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Shkiper50 [21]
2 years ago
9

I need help with this question

Mathematics
1 answer:
AlexFokin [52]2 years ago
3 0
A
Find the two intersections of the lines. The value of x of the intersections will satisfy the system of equations.
Brainliest pls!
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Ellla and some friends are going to a movie. Each movie ticket cost 5 dollars. Create an a equation that shows the relationship
ra1l [238]

Answer:

5n=c

Step-by-step explanation:

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Which statement about the intersecting line and segment Is false?
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Answer:i think there was a pic to go with this to

B(answer)

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What is the fifth square root of x^16
melamori03 [73]
The fifth square root as in a^(1/2)^(1/2)^(1/2)^(1/2)^(1/2)

Well that is equal to a^((1/2)^5) or a^(1/32)

Since a=x^16 in this case and the rule (b^a)^c=b^(a*c) we have:

(x^16)^(1/32)

x^(16/32)

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√x


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3 years ago
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shusha [124]

Answer:

84

Step-by-step explanation:

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A fence is to be built to enclose a rectangular area of 1800 square feet. The fence along three sides is to be made of material
drek231 [11]

Answer:

length = 60 foot, width = 30 foot

Step-by-step explanation:

Area of rectangular part, A = 1800 ft²

Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.

Let the length of the rectangle is l and the width of the rectangle is W.

Area = Length x width

A = L x W

1800 = L x W ...... (1)

Total cost of fencing, C = 6 x ( L + W + L) + 18 x W

C = 6 (2L + W) + 18 W

C = 12 L + 24 W

Substitute the value of W from equation (1), W=\frac{1800}{L} in equation (2)

C=12L+24\times \frac{1800}{L}

C=12L+\frac{43200}{L}

Differentiate both sides with respect to L:

\frac{dC}{dL}=12-\frac{43200}{L^{2}}

Put it equal to zero for maxima and minima

12-\frac{43200}{L^{2}}=0

L = 60 foot

and W = 30 foot

So, the costing is minimum for length = 60 foot and the width = 30 foot.

4 0
3 years ago
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