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2 years ago

The radius of a circle is 9 miles. What is the circle's area?

Mathematics

2 answers:

Assoli18 [71]2 years ago

7 0

Answer:

254.34 miles²

Step-by-step explanation:

How do we find the area of a circle?

The area of a circle can be found using πr², where r = radius. We have the radius as 9 miles, and pi is shortened to 3.14.

<u>Solving</u>

<u></u> $3.14*9^2$
$3.14*81$
$254.34$

Therefore, the area is 254.34 miles².

Have a lovely rest of your day/night, and good luck with your assignments! ♡

kondor19780726 [428]2 years ago

5 0

Answer:

Formula for area of a circle:

πr^2,

where pi is equal to 22/7 or 3.14

and r is the radius that is being squared

Plug in the actual values to this formula to find the area;

a = πr^2

a = 3.14 x 9^2

a = 3.14 x 81

a = 254.34, your answer is 254.34 square miles.

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De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de

Sunny_sXe [5.5K]

Answer:

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

$M \propto \frac{r^{3}}{T^{2}}$

$M = k\cdot \frac{r^{3}}{T^{2}}$ (Eq. 1)

Donde:

$r$ - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

$T$ - Período oribital del satélite, medido en días.

$k$ - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

$M$ - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

$\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }$

$\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}$ (Eq. 2)

Donde:

$T_{M}$ , $T_{E}$ - Períodos orbitales de la Luna y la Tierra, medidos en días.

$r_{E}$ , $r_{M}$ - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

$M_{S}$ , $M_{E}$ - Masas del Sol y la Tierra, medidos en kilogramos.

Si $M_{E} = 75.97\times 10^{24}\,kg$ , $T_{E} = 365.3\,d$ , $T_{M} = 27.3\,d$ , $r_{M} = 3.84\times 10^{5}\,km$ y $r_{E} = 1.496\times 10^{8}\,km$ , entonces tenemos que la masa del Sol es:

$M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}$

$M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)$

$M_{S} = 2.509\times 10^{31}\,kg$

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

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<h3>Answer: 18</h3>

==========================================================

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2 cm on paper (or on screen) represents 3 meters in real life.

The backyard is 2 cm horizontally across on the screen, so it's 3 meters across in real life. This is the shorter dimension.

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