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ElenaW [278]
3 years ago
6

HELP WITH THESE SERIES OF QUESTIONS!!

Mathematics
1 answer:
Virty [35]3 years ago
5 0
1. Simplified already
2. 5x^2 x (3x+5)
3. 3x^3 x (3x^4 +11)
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At which root does the graph of f(x)=(x+4)^6(x+7)^5 cross the x-axis ?
Sindrei [870]

Answer:

Step-by-step explanation:

=4

4 0
3 years ago
Read 2 more answers
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
(2x+3y)²+(2x-3y)²
Natasha_Volkova [10]

Answer:

<h3>d) </h3><h3>2 ({(2x)}^{2}  +  {(3y)}^{2} ) \\</h3>

Step-by-step explanation:

{(2x + 3y)}^{2}  +  {(2x - 3y)}^{2}  \\ (2x + 3y)(2x + 3y) + (2x - 3y)(2x - 3y) \\ 2x(2x + 3y) + 3y(2x + 3y) + 2x(2x - 3y) - 3y(2x - 3y) \\  {4x}^{2}  + 6xy + 6xy +  {9y}^{2}  +  {4x}^{2}  - 6xy - 6xy  +  {9y}^{2}  \\  {4x}^{2}  + 12xy +  {9y}^{2}  +  {4x}^{2}  - 12xy   +   {9y}^{2}  \\  {4x}^{2} +  {9y}^{2}   +  {4x}^{2}   +  {9y}^{2} \\ {8x}^{2}  +  {18y}^{2}  \\ 2( {4x}^{2}  +  {9y}^{2} ) \\ 2( {2}^{2}  {x}^{2}  +  {3}^{2}  {y}^{2} ) \\ 2({(2x)}^{2} + {(3y)}^{2}) \\

4 0
2 years ago
Select the expression that is equivalent to the following:<br> 12^-6 × 12^-5
Radda [10]
The solution to this problem is 743008370688
5 0
3 years ago
Samantha measured 40 1/2 inches. Over the next 5 1/2 years, she grew to a height of 57 inches. During the 5 1/2 years, what was
Alexxandr [17]

Answer:3 in. per yr

Step-by-step explanation:

Present height of Samantha is 40\frac{1}{2}=\frac{81}{2}

After next 5\frac{1}{2} years i.e. \frac{11}{2} years

she grew to 57\ inches

Increase in her height=57-\frac{81}{2}=16.5\ inches

Increase in height per year is =\frac{16.5}{5.5}=3\ in.\ per\ year

3 0
3 years ago
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