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3 years ago

1001 divided by 7 ( long division )

Mathematics

2 answers:

Vilka [71]3 years ago

8 0

Answer:

try 143

Step-by-step explanation:

GREYUIT [131]3 years ago

3 0

Answer: 143

Step-by-step explanation: hope this helps :)

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A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet awa

tatuchka [14]

Answer:

Second puck travels farther

Step-by-step explanation:

Maximum height of first puck = 3 feet

The height of a second hockey puck is modeled by:

$y=x\left(0.15-0.001x\right)$

$y=0.15x-0.001x^2$

To find maximum height of second puck

$y'=0.15-0.002x$

Equate the derivative equals to 0

0.15-0.002x=0

$\frac{0.15}{0.002}=x$

75 = x

At x = 75

$y=0.15(75)-0.001(75)^2=5.625$

So, The maximum height of second puck is greater than first puck

So, Second puck travels farther

5 0

3 years ago

G(x) = 1/3 * (2/9)^x. Does the function model growth or decay?

ElenaW [278]

The function models Exponential Decay due to the fact that as

x -> infinity, y-> 0

4 0

3 years ago

How do you find the area of the shaded sector of the circle? The radius is 10in and the sector is 45 degrees

Step2247 [10]

Given:

Radius of the circle = 10 in

Central angle of the sector = 45 degrees

To find:

The area of the sector.

Solution:

Area of a sector is

$A=\dfrac{\theta}{360^\circ}\pi r^2$

Where, $\theta$ is the central angle in degrees.

Putting r=10 and $\theta=45^\circ$ , we get

$A=\dfrac{45^\circ}{360^\circ}\pi (10)^2$

$A=\dfrac{1}{8}\pi (100)$

$A=12.5\pi$

Therefore, the area of the sector is 12.5π sq. inches.

7 0

3 years ago

This season, Lisa's lacrosse team has won $\frac 23 of their home games (games played at Lisa's school), but just $\frac 25 of t

juin [17]

Answer:

Lisa's team have played 24 home games and 25 away games.

Step-by-step explanation:

Given:

Let $x$ represents games played at home.

also $y$ represent games played away.

Total number of games played = 49

∴ $x+y=49 \ \ \ \ equation \ 1$

Now according to given data:

Number of home games won = $\frac{2}{3}$

Number of away game won = $\frac{2}{5}$

Total games won =26

Hence

$\frac{2}{3}x+\frac{2}{5}y=26\\\\\frac{2\times 5}{3\times 5}x+\frac{2\times 3}{5\times 5}y=26\\\\\frac{10}{15}x+\frac{6}{15}y=26\\\\\frac{10x+6y}{15}=26\\\\10x+6y= 26\times 15\\10x+6y = 390\\2(5x+3y)=390\\5x+3y=\frac{390}{5}\\\\5x+3y=195 \ \ \ \ equation \ 2\\$