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Anni [7]
2 years ago
7

What operation would you do first to simplify 4 × 3 - 3 to the second power + 1 × 8​

Mathematics
1 answer:
True [87]2 years ago
6 0

Answer:

4 × 3 - 3^2 + 1 × 8 = 11/1 = 11

Step-by-step explanation:

Multiple: 4 * 3 = 12

Exponentiation: 3 ^ 2 = 9

Subtract: the result of step No. 1 - the result of step No. 2 = 12 - 9 = 3

Multiple: 1 * 8 = 8

Add: the result of step No. 3 + the result of step No. 4 = 3 + 8 = 11

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Need answer now. Find m
balandron [24]
Answer: 61°

180-119 = 61
4 0
2 years ago
-1/3/4 + 1/1/6 equals what in fractions
Gnesinka [82]

Step-by-step explanation:

Simplify fractions on fractions

\frac{1}{ \frac{3}{4} }

Multiply by the inverse of denominator

\frac{4}{3}

Simplify fractions on fractions

\frac{1}{ \frac{1}{6} }

Multiply by the inverse of denominator

6

Add both sides

-  \frac{4}{3}  + 6

8 0
3 years ago
The diameter of steel rods manufactured on two different extrusion machines is being investigated. Two random samples of sizes
devlian [24]

Answer:

(a) There is no evidence to support the claim that the two machines produce rods with different mean diameters.

P-value is 0.818

(b) 95% confidence interval for the difference in mean rod diameter is (-0.17, 0.27).

This interval shows that the difference in mean is between -0.17 and 0.27.

Step-by-step explanation:

(a) Null hypothesis: The two machines produce rods with the same mean diameter.

Alternate hypothesis: The two machines produce rods with different mean diameter.

Machine 1

mean = 8.73

variance = 0.35

n1 = 15

Machine 2

mean = 8.68

variance = 0.4

n2 = 17

pooled variance = [(15-1)0.35 + (17-1)0.4] ÷ (15+17-2) = 11.3 ÷ 30 = 0.38

Test statistic (t) = (8.73 - 8.68) ÷ sqrt[0.38(1/15 + 1/17)] = 0.05 ÷ 0.218 = 0.23

degree of freedom = n1+n2-2 = 15+17-2 = 30

Significance level = 0.05 = 5%

Critical values corresponding to 30 degrees of freedom and 5% significance level are -2.042 and 2.042.

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.23 falls within the region bounded by the critical values -2.042 and 2.042.

There is no evidence to support the claim that the two machines produce rods with different mean diameters.

Cumulative area of test statistic is 0.5910

The test is a two-tailed test.

P-value = 2(1 - 0.5910) = 2×0.409 = 0.818

(b) Difference in mean = 8.73 - 8.68 = 0.05

pooled sd = sqrt(pooled variance) = sqrt(0.38) = 0.62

Critical value (t) = 2.042

E = t×pooled sd/√n1+n2 = 2.042×0.62/√15+17 = 0.22

Lower limit of difference in mean = 0.05 - 0.22 = -0.17

Upper limit of difference in mean = 0.05 + 0.22 = 0.27

95% confidence interval for the difference in mean rod diameter is between a lower limit of -0.17 and an upper limit of 0.27.

3 0
3 years ago
A triangular pane of glass has a height of 30 inches and an area of 270 square inches. what is the length of the base pane
Tems11 [23]
The equation for the area of a triangle is A= b*h /2. So, plug in your known variables, and you get 270in^2= b*30 /2. First you multiply by 2 to cancel out the division for 2, which gets you 540= b* 30. To get "b" by itself, divide both sides by 30, giving you <u>18=b</u>.

To check this, plug in your new known variable, as 270= 18* 30 /2. This will equal as 270=270, confirming 18in as the correct measurement.
3 0
3 years ago
A college bookstore charges $60 for a yearly membership. The first book is free with membership and any book after that costs $7
brilliants [131]

Answer:

The equation representing Total money spend being as a member is m = 60+7.6(b-1)

Step-by-step explanation:

Given:

Memberships charges = $60

Cost of 1 book = $7.60

Let number of books be 'b'.

We need to find Total money 'm' spend yearly on buying books after becoming member.

Now we know that 1 book is free for a member.

Total money spend 'm' will be equal to Sum Memberships charges  and Cost of 1 book multiplied by number of books bought yearly minus 1.

Framing in equation form we get;

m = 60+7.6(b-1)

Hence The equation representing Total money spend being as a member is m = 60+7.6(b-1)

5 0
3 years ago
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