To solve this problem, we make use of the formula of
combination.
nCr = n! / r! (n – r)!
where n is the total number of subject teachers and r is
the number of subjects r = 1
For the English class n = 3
3C1 = 3! / 1! (3 – 1)! = 3
For the Algebra class n = 4
4C1 = 4! / 1! (4 – 1)! = 4
For the Biology class n = 2
2C1 = 2! / 1! (2 – 1)! = 2
The total number of different schedules would be the
product of the three combinations:
total combinations possible = 3 * 4 * 2
total combinations possible = 24
Answer:
1= 0
2= 0.5
3= 1.5
4= 3
5= 5
6= 7.5
7= 10.5
8= 14
explanation: This is the edmentum answer
Answer:
y = 95
Step-by-step explanation:
x + 120 = 180
25 + x + y = 180
flipping the first equation 180 - 120 = 60 so x is 60.
so plug in 60 into the second equation
25 + 60 + y =180 --> 85 + y =180 flip equation 180 - 85 = 95
so y is 95