a. Ryan's rate of change is <em>$15 per month;</em>
Taylor's rate of change is <em>$20 per month</em>
b. Ryan's starting balance is <em>$50</em>;
Taylor's starting balance is <em>$25.</em>
<em><u>Recall:</u></em>
- A linear function is modelled by the equation, y = mx + b, where m is the rate of change and b is the initial value (starting value).
- Rate of change = change in y/change in x
<u><em>Ryan's Savings Plan </em></u><u><em>Function</em></u><u><em>:</em></u>
s = 15m + 50
Thus, the starting value (starting balance) modelled by this function is $50
The slope/rate of change is $15 per month
<em><u>Taylor's Savings Plan:</u></em>
Given the table, the starting value will be the amount saved (initial value) at 0 number of months.
- Therefore, Taylor's starting balance is: $25
Using (0, 25) and (1, 45) find the rate of change:
- Rate of change = (45 - 25)/(1-0) = 20/1 = $20
In summary:
a. Ryan's rate of change is <em>$15 per month;</em>
Taylor's rate of change is <em>$20 per month</em>
b. Ryan's starting balance is <em>$50</em>;
Taylor's starting balance is <em>$25.</em>
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