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san4es73 [151]
3 years ago
5

Please help me! Write an equation in point-slope form of the line that passes through the given point and has the given slope.

Mathematics
1 answer:
andriy [413]3 years ago
8 0

9514 1404 393

Answer:

  1. y -3 = 5(x -1)
  2. y +1 = -3(x +2)
  3. y +7 = -1/4(x -4)

Step-by-step explanation:

When you are given a point and a slope, and asked for the equation in point-slope form, it is simply a matter of putting the given numbers into the appropriate places in the equation template.

  y -k = m(x -h) . . . . . . point (h, k), slope m

__

1. y -3 = 5(x -1) . . . . . . point (1, 3), slope 5

2. y +1 = -3(x +2) . . . . point (-2, -1), slope -3

  note that for k=-1, -k = -(-1) = +1; similarly the value of -h becomes +2

3. y +7 = -1/4(x -4) . . . point (4, -7), slope -1/4

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\bf \textit{sum of all interior angles of a polygon}\\\\
180(n-2)\quad 
\begin{cases}
n=\textit{number of sides}\\
---------\\
n=10
\end{cases}\implies 180(10-2)\implies 1440\\\\
-------------------------------\\\\
\begin{array}{lclll}
&x + 5\\&x + 10\\&x + 20\\&x + 30\\&x + 35\\&x + 40\\&x + 60\\&x + 70\\&x + 80\\+&x + 90\\
&----\\
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