Calculate the molarity of 0.5 moles NaHCO3<br> in 5,314 mL of solution.<br> How do I solve this?

What element is in the 3 rd period and 7th family

aleksley [76]

Pokémon is it that's the anwser

4 0

3 years ago

Which statement accurately describes the origin and expansion of the universe? As the universe continues to expand, it gradually

dimulka [17.4K]

The answer is; Cosmic background radiation is leftover thermal energy from the big bang.

Called the coming microwave background the weak radiation fills the universe more or less uniformly. This radiation is the fossil remnants of the postulated big band at the beginning of the universe. The photos produced at the time continue to travel through the universe growing fainter over time and have fallen in the microwave range of the electromagnetic spectrum now.

5 0

3 years ago

Read 2 more answers

Identify a process that is NOT reversible. A. melting of steel B. freezing water C. melting of ice D. frying an egg E. depositio

vredina [299]

I’m pretty sure it would be D. Frying an egg

8 0

4 years ago

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

10. The statement that no two electrons in the same atom can have the

Fynjy0 [20]

Answer:

10.the pauli exclusive principle statues that, in an atom

or molecules, no two electrons can have same four electronic quantum numbers.as an orbit can contain a maximum of only two electrons.the two electrons must have opposing spins

3 0

3 years ago

Calculate the molarity of 0.5 moles NaHCO3 in 5,314 mL of solution. How do I solve this?