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Stolb23 [73]
3 years ago
7

Dawn is comparing how different animals move and the structures they use to move. She made the table shown below.

Chemistry
1 answer:
Dovator [93]3 years ago
6 0

Answer:

tail and fins

Explatanation:

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The more quickly you change your _____, the more ____ you will have to exert
tatyana61 [14]

Answer:

name, force

Explanation:

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2 years ago
Ants live on acacia trees in South America. The ants feed on sugars secreted by the trees. The trees provide room for the ants t
Stolb23 [73]
Mutualism! The tree provides a home and food for the ants, while the ants protect the tree :)
8 0
2 years ago
Draw the structure of the following three isomeric esters with chemical formula C7H12O2. Ester #1: methyl 1-methylcyclobutanecar
marissa [1.9K]

Answer:

The following three isomeric structure are given below.

Explanation:

Structure of the following three isomeric esters with chemical formula C₇H₁₂O₂

Ester #1: methyl 1-methylcyclobutanecarboxylate

Ester #2: (E)-methyl 3-methyl-3-pentenoate

Ester #3: isopropyl 2-methylpropenoate                

6 0
3 years ago
What is a problem that would likely occur if two cultures had different calenderars
aksik [14]
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3 0
3 years ago
Read 2 more answers
For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

3 0
2 years ago
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