The correct answer is - D. Savannah is more humid and has higher precipitation than San Diego.
Despite both Savannah and San Diego being on the coast of an ocean, they do have differences in the climate. Savannah comes out on the Atlantic coast, while San Diego comes out on the Pacific Coast. Savannah is influenced by warm and wet air masses all year round, while San Diego is predominantly influenced by dry air masses because of the colder ocean currents. Savannah has a relatively stable temperature throughout the year, and it also has solid amount of precipitation, with the humidity in the air being always high. San Diego, on the other side, is hot for most of the year during the days, but the nights are relatively cool. There's very little precipitation, and the humidity in the air is not as high as in Savannah.
The shape of the hydrophobic tail creates a kink. Some double bonds between some of the carbons in the hydrocarbon tail, cause bends or “kinks” in the shape of the molecules. Because some of the carbons share double bonds, they’re not bonded to as many hydrogen as they could if they weren’t double bonded to each other.
Answer:
Explanation:
Did you mean: V = d/t a = (V - Vit Average = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = -9.81 m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?
Showing results for V = d/t a = (V - Vil/t Vaverage = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = "-9.81" m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?
Search instead for V = d/t a = (V - Vil/t Vaverage = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = -9.81 m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?
1) Balanced chemical reaction: 2NH₃ + 3N₂O → 3H₂O + 4N₂.
<span>According to principle of mass conservation, n</span>umber of atoms must be equal on both side of chemical reaction. There are eight nitrogen atoms, six hydrogen atoms and three oxygen atoms on both side of reaction, so chemical reaction is balanced.
2) ΔrH = ∑ΔfH(products) - ∑ΔfH(reactants).
ΔrH = 3·ΔfH(H₂O) + 4·ΔfH(N₂) - (2·ΔfH(NH₃) + 3·ΔfH(N₂O).
ΔrH = 3 mol ·(-285,5 kJ/mol) + 4 mol·(0 kJ/mol) - (2mol·(-46,1 kJ/mol) + 3mol·(82,05 kJ/mol)).
ΔrH = -1011,4 kJ.
Ideal gas law: p·V = n·R·T.
p = 100000 Pa = 0,987 atm.
T = 298,15 K.
V = 345 mL = 0,345 L.
R = 0,08206 L·atm<span>/mol·K.
n(N</span>₂) = 0,987 atm · 0,345 L ÷ 0,08206 L·atm/mol·K · 298,15 K.
n(N₂) = 0,014 mol.
4 mol : -1011,4 kJ = 0,014 mol : ΔH.
ΔH = -3,51 kJ.
