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Lina20 [59]
3 years ago
11

Consider the bonding properties of the three compounds

Chemistry
1 answer:
Vilka [71]3 years ago
3 0

Answer:

CO3^2- has the weakest C-O bond

Explanation:

Hybridization is a valence bond concept that has to do with the mixing of atomic orbitals to give hybrid atomic orbitals suitable for overlapping with orbitals of other atoms to form molecules. The hybridization of the carbon atom in CO, CO2 and CO3^2- are; sp, sp and sp2. This implies that there must be pi bonding in each of the species since sp and sp2 hybridized carbon atoms are known to lead to molecules possessing pi bonds.

In CO2, carbon in sp hybridized state is bonded to two oxygen atoms in sp2 hybridized state leading to a double bond between carbon and each oxygen atom. In CO, the carbon atom is sp hybridized while the oxygen atom is sp2 hybridized. CO3^2- contains an sp2 hybrized carbon atom in a trigonal planar geometry.

The relative bond lengths of the C-O bond in CO2, CO and CO3^2- is 116 pm, 112.8 pm and 136pm. Hence CO3^2- has the longest bond length. Remember that bond length is inversely proportional to the bond order. That is, the shorter the bond length, the greater the bond order. This implies that CO will have the greatest bond order because it shows the shortest bond length. It turns out that CO has a bond order of 3, CO2 has a bond order of 2 and CO3^2- has a bond order of 1.33. This is intermediate between the bond order of single and that of double C-O bond hence CO3^2- is represented using resonance structures.

The species with the longest C-O bond length also has the weakest C-O bond hence CO3^2- has the weakest C-O bond.

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3 years ago
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A 45.0-gram sample of copper metal was heated from 20.0°C to 100.0°C. Calculate the heat absorbed, in kJ, by the metal.
s2008m [1.1K]

Answer:

1.386 KJ

Explanation:

From the question given above, the following data were obtained:

Mass (M) of copper = 45 g

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

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Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Change in temperature (ΔT) =?

ΔT = T2 – T1

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Next, we shall determine the heat absorbed by the sample of copper as follow:

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Heat absorbed (Q) =..?

Q = MCΔT

Q = 45 × 0.385 × 80

Q = 1386 J

Finally, we shall convert 1386 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

1386 J = 1386 J × 1 KJ /1000 J

1386 J = 1.386 KJ

Thus, the heat absorbed by the sample of the sample of copper is 1.386 KJ.

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3 years ago
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Answer:

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Explanation:

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