Question

A mass of 2.20 g carbon monoxide is reacted with 4.86 g hydrogen to form methanol.CO(g) + 2 H2(g) → CH3OH(g)The reaction is performed in a 5.00 L flask at 85.0 °C and proceeds to completion. What is the partial pressure (in mmHg) of each of the three species following completion of the reaction? What is the total pressure in the flask?

Answer 1

Answer:

The partial pressure in mm Hg for each of the species are:

PCO = 0

PH2 = 3874

PCH3OH = 347

The total pressure is 4221

Explanation:

We have to use Ideal gas equation PV = nRT and Partial pressure rule Total Pressure= ∑ Partial pressures.

We have following data:

T= 357K (85+272); nCO=0.078 (2.2/28); nH2 = 2.43 (4.86/2); R=62.36

With equation CO(g) + 2 H2(g) → CH3OH(g) we can calculate the amount of moles the reaction has finished. The limit reagent is CO because is consumed completely and moles CO in flask are 0. According to equation, every CO mol produces one CH3OH mol. That means 0.078 CO moles produces 0.078 CH3OH moles. From Ideal gas equation we have P=nRT/V.

Applying:

PH2=0.87*62.36*357/5=3874

PCH3OH =0.078*62.36*357/5=347

Total P = 3874+347=4221

I hope my answer helps you