Cost per mole
Table salt : Rs 0.878
Table sugar : Rs 23.63
<h3>Further explanation</h3>
Given
Cost table salt (NaCl) = 15/kg
Cost table sugar(sucrose-C12H22O11) = 69/kg
Required
cost per mole
Solution
mol of 1 kg Table salt(NaCl ,MW= 58.5 g/mol) :
mol of 1 kg Table sugar(C12H22O11 ,MW= 342 g/mol) :
Answer:
78.125ml
Explanation:
Number of moles in 250ml of 2.5M KCl is (250÷1000)litres×2.5M so we divide these moles by 8M. The answer gotten will be in litres so multiply by 1000 to get it in ml
Answer: Radiant energy to chemical energy. Explanation: Photosynthesis is known for the radiant energy transformation into chemical energy. It is a process where plants to take in sunlight, water, & CO2 and convert them into oxygen, and glucose, in this process CO2 is removed from the air. In the process of photosynthesis, the energy that is captured by the sun is stored in the form of carbohydrates. The photosynthesis process occurs in the chloroplast which is present in the plants, and the pigment is known as chlorophyll which helps to make plant green.
Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/292637-type-of-energy-transformed-into-chemical-energy-by-plants.html
Answer:
0.0847M is molarity of sodium hydrogen citrate in the solution
Explanation:
The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.
<em>Moles Na2C6H6O7:</em>
<em>Molar Mass:</em>
2Na: 2*22.99g/mol: 45.98g/mol
6C: 6*12.01g/mol: 72.01g/mol
6H: 6*1.008g/mol: 6.048g/mol
7O: 7*16g/mol: 112g/mol
45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol
Moles of 2g:
2g * (1mol / 236.038g) = <em>8.473x10⁻³ moles</em>
<em />
<em>Liters solution:</em>
100mL * (1L / 1000mL) = <em>0.100L</em>
<em>Molarity:</em>
8.473x10⁻³ moles / 0.100L =
<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>
