The solution to x+5/4x> 3 is any real number except 0. O True O False

What is the value of 3x 2 squared + 5x when x=3

Serhud [2]

3•2=6. When you square 6, you get 36. Add 5x to that. 5x=15. 36+15=51

Cassie read 155 pages one day, and we need to find the unknown value of “x”. All you have to do is add 155+x=325.

6 0

3 years ago

12-7(8*9) 82 5-82 -77 <img src="https://tex.z-dn.net/?f=12%20-%207%288x9%29%20%3D%20" id="TexFormula1" title="12 -

Goryan [66]

Well, that's incorrect because according to the Order of Operation [GEMS\BOMDAS\PEMDAS etc.], that -7 has to be distributed amongst all the other terms in parentheses. Besides, you did the wrong operation when you inserted that subtraction symbol in substitution of the parentheses, which means to MULTIPLY. So, the order goes as follows:

12 - 7[72]

-504 + 12 = -492 [OR 12 - 504]

-492 is your answer. You get it now?

3 0

3 years ago

The temperature fell from 0 Degrees Fahrenheit to 15 and one-half Degrees Fahrenheit below 0 in 5 and three-fourths hours. Wen t

Kryger [21]

Answer:

The correct answer will be:

$-\dfrac{62}{23}$

Step-by-step explanation:

It is given that :

Initial temperature, $T_1 = 0^\circ F$

Final temperature,

$T_2 = -15\dfrac{1}{2}^\circ F\\\Rightarrow T_2 = -\dfrac{15\times 2+1}{2} ^\circ F\\\Rightarrow T_2 = -\dfrac{31}{2} ^\circ F$

Time taken :

$5\dfrac{3}{4}\ hrs = \dfrac{5 \times 4+3}{4}\ hrs = \dfrac{23}{4}\ hrs$

Change in temperature per hour:

$\dfrac{\text{Difference of temperature}}{\text{Total Time Taken}}\\\Rightarrow \dfrac{T_2-T_1}{\text{Total Time Taken}}$

Putting the values of temperatures and time:

$\dfrac{\dfrac{-31}{2}-0}{\dfrac{23}{4}}\\\Rightarrow \dfrac{\dfrac{-31}{2}}{\dfrac{23}{4}}\\\Rightarrow \dfrac{-31 \times 4}{2 \times 23}} \text{---- Error done by Wen at this step}\\\Rightarrow \dfrac{-31 \times 2}{23}}\\\Rightarrow \dfrac{-62}{23}}$