By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
Given that, a║b and both the lines are intersected by transversal t.
We need to prove that m∠1=m∠5.
<h3>What is a transversal?</h3>
In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.
m∠1+m∠3= 180° (Linear Pair Theorem)
m∠5+m∠6=180° (Linear Pair Theorem)
m∠1+m∠3=m∠5+m∠6
m∠3=m∠6
m∠1=m∠5 (Subtraction Property of Equality)
Hence, proved. By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
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Once you plug in -18 as x you divide it with 6 and the answer of that is -3 then you add 17 and -3 and your output will be 14!
Answer:
Vertex form
Step-by-step explanation:
You convert to vertex form a(x - b)^2 + c . The coordinates of the maxm/minm will be (b, c).
For example find minimum value of x^2 + 5x - 6:-
x^2 + 5x - 6
= (x + 2.5)^2 - 6.25 - 6
= (x + 2.5)^2 - 12.25
The coordinates of minimumm will be (-2.5, -12.25) The values of the minimum of the function is -12.25