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2 years ago

Part 2 HELP PLZ tHIS HARd

Mathematics

1 answer:

natita [175]2 years ago

6 0

You have to find the mean median and mode with the three day period and the four day period and compare them.

I believe that unless I did something wrong, the answer is B!

Hope this helps,

CK :)

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Sqrt(3x)-1=-4 1.)x=3 2.)x=-3 3.) no solution 4.)x= 25/3

shtirl [24]

The correct Answer Is NO SOLUTION

8 0

3 years ago

Find an exponential function with a horizontal asymptote y equals=2 whose graph contains the points (0,3) and (1,6).

Andrew [12]

$\bf y=a(b)^x\qquad \qquad (\stackrel{x}{0}~,~\stackrel{y}{3})\implies 3=a(b)^0\implies 3=a
\\\\\\
therefore\qquad y=3(b)^x\\\\
-------------------------------\\\\
(\stackrel{x}{1}~,~\stackrel{y}{6})\implies 6=3(b)^1\implies \cfrac{6}{3}=b^1\implies 2=b
\\\\\\
therefore\qquad y=3(2)^x$

now, exponential functions have a horizontal asymptote at the x-axis, namely when y = 0, however, if you just move this one with a vertical translation of 2, then the horizontal asymptote will be at 2 instead. y = 3(2)ˣ + 2

6 0

3 years ago

!!!!!!!!!! PLEASE HELP IM SO FRUSTRATED

Kay [80]

that's alot of questions

3 0

2 years ago

Read 2 more answers

Hello,..... I will mark you as a brainliest

madam [21]

Answer:

5 jumps

Step-by-step explanation:

Personally I would write it out, although there surely is a formula for it.

3 fall to 2 - 5 fall to 4 - 7 fall to 6 - 10 fall to 9 - 12.

This makes 5 jumps, since once he is out he won't fall back in.

8 0

2 years ago

After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only three women among the last

mixer [17]

Answer:

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

Step-by-step explanation:

For each employee hired, the are only two possible outcomes. Either it is a man, or it is a woman. The probability of a person hired being a man or a woman is independent of any other person. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

21 new employees.

This means that $n = 21$

She also learns that the pool of applicants is very large, with an approximately equal number of qualified men as qualified women.

This means that $p = 0.5$

Help her address the charge of gender discrimination by finding the probability of getting three or fewer women when 21 people are hired.

This is

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{21,0}.(0.5)^{0}.(0.5)^{21} \approx 0$

$P(X = 1) = C_{21,1}.(0.5)^{1}.(0.5)^{20} = 0.00001$

$P(X = 2) = C_{21,2}.(0.5)^{2}.(0.5)^{19} = 0.0001$

$P(X = 3) = C_{21,3}.(0.5)^{3}.(0.5)^{18} = 0.0006$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.00001 + 0.0001 + 0.0006 = 0.00071$

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

8 0

3 years ago