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LekaFEV [45]
2 years ago
13

What is the median of this data set?

Mathematics
2 answers:
bazaltina [42]2 years ago
7 0

Answer:

14

Step-by-step explanation:

Because the median is the middle number when the data set is in order least to greatest so you already have it in least to greatest so thank you for helping me.

and for extra just in case.

Mean=16.222

the mean= the average of the data set

Mode is 13,14

The mode is the number that appears the most in a data set and 13 and 14 appear twice.

Your range is=13

Range is the highest number subtracting the lowest number so 24 -11 which =13

Minimum is 11 because the minimum is the lowest number in data set..

Maximum is 24

Maximum is the highest number in the data set.


I hope this helps have a awesome day:)

Paladinen [302]2 years ago
4 0
16.2 when rounded to a whole number becomes 16
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Derivatives concept:<br> Exercise "position and instantaneous velocity"<br><br> (Full development)
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(A) The blue line has a slope of 5/2, red has slope 4/4 = 1, and purple has slope 3/9 = 1/3.

To find the slope, take any two points <em>(a, b)</em> and <em>(c, d)</em> on the line, then

slope = (<em>d</em> - <em>b</em>)/(<em>c</em> - <em>a</em>)

i.e. the ratio between the changes in the <em>y</em> and <em>x</em> coordinates.

(B) Each line has equation

• blue: <em>y</em> = 5/2 <em>x</em>

• red: <em>y</em> = <em>x</em>

• purple: <em>y</em> = 1/3 <em>x</em>

This follows from the general equation for a line with slope <em>m</em> and <em>y</em>-intercept <em>b</em>,

<em>y</em> = <em>mx</em> + <em>b</em>

or from the <em>more</em> general equation for a line with slope <em>m</em> passing through a point <em>(a, b)</em>,

<em>y</em> - <em>b</em> = <em>m</em> (<em>x</em> - <em>a</em>)

(C) Consider the blue line. If you take units into account, its slope is

(5 units of distance)/(2 units of time) = 5/2 (units of distance/time)

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(D) The competitor with the blue line, Mary, would win the race because their speed is the highest (5/2 > 1 > 1/3).

(E) Average velocity is defined as

<em>v</em> (ave) = ∆<em>d</em>/∆<em>t</em> = (change in distance)/(change in time)

At time 0, no one has moved yet. At time 4,

• Mary has covered a distance of 5/2 × 4 = 10, giving her an average velocity of (10 - 0)/(4 - 0) = 5/2

• Mike has covered a distance of 4, so his average velocity is (4 - 0)/(4 - 0) = 1

• Sam has covered a distance of 1/3 × 4 = 4/3, so his average velocity is (4/3 - 0)/(4 - 0) = 1/3

It's not a coincidence that the average velocities are the same as the slopes, because each racer travels at a constant speed.

(F) The racers' instantaneous velocities are the same as their respective average velocities, again because they are each moving at a constant speed.

7 0
3 years ago
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