Answer:
the answer is 85.33π cm
Step-by-step explanation:
Assuming that the center of each circle is at point C and D, then both have a radius of 7cm. We know that the formula for solving area of the circle is A=pi*r².
Then we solve area of once circle multiplied by two to get the total area of the given circles. The solution is shown below:
C1 area=3.1416*7²
C1 area=153.9384 cm²
Summation of the area of circle C and D is shown below:
Sum area=2*153.9384
Sum area=307.8768cm²
The answer is 98pi.
Answer:
Base=8 feet
Height=17 feet
Step-by-step explanation:
Let
Base=x
Height=3x-7
Area=68 square feet
Area of the sail boat=1/2 * base * height
68 = 1/2 * x * (3x-7)
Cross product
68 * 2 =(1) * (x) * (3x-7)
136 = 3x^2 - 7x
3x^2 - 7x - 136=0
Using quadratic formula
x= -b +or- √b^2 - 4ac / 2a
= -(-7) +or- √(-7)^2 - (4)(3)(-136) / 2(3)
= 7 +or- √49 - (-1632) / 6
= 7 +or- √49+1632) / 6
= 7 +or- √1681 / 6
=7 +or- 41 /6
x= 7+41 / 6 or 7-41 / 6
=48/6 or -34/6
=8 or -17/3
Answer:
Step-by-step explanation:
Let
Base=x
Height=3x-7
Area=68 square feet
Area of the sail boat=1/2 * base * height
68 = 1/2 * x * (3x-7)
Cross product
68 * 2 =(1) * (x) * (3x-7)
136 = 3x^2 - 7x
3x^2 - 7x - 136=0
Base of the boat can't be a negative value
Therefore,
Base = x = 8 feet
Height= 3x-7
=3(8)-7
=24-7
=17 feet
Answer: x=0.6435011
Step-by-step explanation:
Take the inverse tangent of both sides of the equation to extract
x
from inside the tangent.
x
=
arctan
(
3
4
)
Evaluate
arctan
(
3
4
)
.
x
=
0.6435011
The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from
π
to find the solution in the fourth quadrant.
x
=
(
3.14159265
)
+
0.6435011
Simplify the expression to find the second solution.
Tap for more steps...
x
=
3.78509376
Find the period.
Tap for more steps...
π
The period of the
tan
(
x
)
function is
π
so values will repeat every
π
radians in both directions.
x
=
0.6435011
+
π
n
,
3.78509376
+
π
n
, for any integer
n
Consolidate the answers.
x
=
0.6435011
+
π
n
, for any integer
n
