It's the zero in the tenth place
Answer: He needs 364 ounces.
Step-by-step explanation:
26 * 1.75 = 45.5
1 cup = 8 ounces
Answer:
∠O = 95°
Step-by-step explanation:
since ∠Q = 85°, arc NOP = 2(85°) = 170°
arc PQN = 360° - arc NOP
arc PQN = 360° - 170° = 190°
∠O = 1/2(arc PQN) = 1/2(190°) = 95°
Answer: x=-2 y=2
Step-by-step explanation:
I decided that isolating the y value of the second equation is the best way to start solving.
I divide 3 from both sides to get y= (4-x)/3. With this, I can substitute into the first equation. 4x+3(4-x)/3)=-2.
The multiplying the 3 by the denominator three cancels each other out to make:
4x+4-x=-2.
We subtract 4 on both sides and then subtract x from 4x.
We end up with 3x=-6. Then, we divide both sides by 3.
x=-2.
Now we substitute this into the second equation to solve.
3y=4-(-2)
This becomes 3y=4+2 which is 3y=6
We divide both sides by 3 to get y=2
We end up with x=-2 and y=2.
I hope you learned something :)
Answer:
14. x=-2.5, y = -7
15. x=28 y = -20
Step-by-step explanation:
14. Let's solve this system by elimination. Multiply the first equation by -1.
-1*(4x-y)= -1*(- 3)
-4x +y = 3
Then add this to the second equation.
-4x+y = 3
6x-y= - 8
--------------
2x = -5
Divide each side by 2
x = -2.5
We still need to find y
-4x+y =3
-4(-2.5) + y =3
10 +y =3
Subtract 10 from each side.
y = 3-10
y = -7
15.I will again use elimination to solve this system, because using substitution will give me fractions which are harder to work with. I will elimiate the y variable. Multiply the first equation by 11
11(
5x+6y)= 11*20
55x+66y = 220
Multiply the second equation by -6
-6(9x+11y)=32*(-6)
-54x-66y = -192
Add the modified equations together.
55x+66y = 220
-54x-66y = -192
---------------------------
x = 28
We still need to solve for y
5x+6y = 20
5*28 + 6y =20
140 + 6y = 20
Subtract 140 from each side
6y = -120
Divide by 6
y = -20
