Complete the point-slope equation of the line through (1,0) and (6,3). Use exact numbers. y-(-3)=

Mathematics

2 answers:

11111nata11111 [884]3 years ago

8 0

Answer:

point-slope equation of the line through (1,0) and (6,-3). Use Exact Numbers

Step-by-step explanation:

FrozenT [24]3 years ago

4 0

Answer:

Step-by-step explanation:

$(1,0) =(x_1,y_1),\\ (6,3)=(x_2,y_2))\\\\\frac{y-y_1}{x-x_1}= \frac{x_2-x_1}{y_2-y_1} \\ \\\\\frac{y-0}{x-1} = \frac{6-1}{3-0} \\\\\frac{y-0}{x-1} = \frac{5}{3}\\\\3(y-0)=5(x-1)\\\\3y -0 =5x-5\\\\3y = 5x-5+0\\\\3y = 5x-5\\\\\frac{3y}{3} = \frac{5}{3} x= \frac{5}{3} \\\\y = \frac{5}{3} x= \frac{5}{3}\\$

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Stolb23 [73]

Answer:

$y-3=-\frac{3}{8} (x+2)$

Step-by-step explanation:

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point (8,1) and a slope from the equation. We will chose point-slope since we have a point and slope.

Point slope: $y-y_1=m(x-x_1)$

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Steps to find the equation
1. Find the slope
2. Insert slope into the general equation
3. Find y-intercept
4. Insert -intercept into the equation found in step 2
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Find the slope
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2y - x = 4

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Rewrite into the form y = mx + c
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2y = x + 4
y = 1/2 x + 2

Slope = 1/2
Perpendicular slope = -2 (negative reciprocal)

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Insert slope into the equation
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y = mx + c
y = -2x + c

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Find y-intercept
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y = -2x + c
At point (1, 2)
2 = -2(1) + c
2 = -2 + c
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Insert y-intercept into the equation y = -2x + c
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y = -2x + 4

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Answer: y = -2x + 4
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