First step
Using substitution you can fill 2x + 11 in for the y part of the first equation
This will look like: 2x + 11 = -x^2 -2x + 8
Second step
Now we need to solve for the variable by combining like terms you can start by adding x^2 + 2x -8 to both sides
You get 0 = x^2 +4x +3
Third step
Factor
(X+3)(x+1)=0
If you need the y values you can fill in x= -3 to the second equation y= 2(-3) + 11 and y=5
First point is (-3,5)
The other point is found by filling x=-1 into the second equation: y= 2(-1) +11 and y = 9
Second point is (-1,9)
Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

By substitution:

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

Zero Product Property:

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
Answer:
690
Step-by-step explanation:
Round from the tens place.
<span>5x-6y=-15
5x+6y=12
---------------add
10x = -3
x = -3/10
x = -0.3
</span>5x+6y=12
5(-0.3) + 6y = 12
6y = 12 + 1.5
6y = 13.5
y = 13.5 / 6
y = 2.25
Just pretend it’s a 3d right angle triangle and find the length of the hypotenuse.
d = sqrt(6^2 + 10^2 + 15^2) = 19