Ask question

Ask question

All categories

3 years ago

7

(Factorize): x²-5x + 6

1 answer:

faltersainse [42]3 years ago

5 0

Factor x
2−5x+6x

using the AC method.
(x−3)(x−2)

You might be interested in

What is the percent that is equal to 0.02

alekssr [168]

2%. You must move the decimal two places to the right.

3 0

3 years ago

Read 2 more answers

What is the length of the rectangle if the perimeter is 102 cm?

elixir [45]

<span> <span>The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width</span></span>

3 0

3 years ago

Read 2 more answers

Maria washes the windows in her house every 2 tweaks, meows her lawn every 3 weeks, and trims her garden bushes every 5 weeks. T

oee [108]

In another 30 weeks, because 2x3x5=30 weeks where she does all of the activities.<span />

4 0

3 years ago

Paul has 144 army man and his toy box into six equal groups for battle how many army men are in each group

iogann1982 [59]

I'm pretty sure this one is super easy
you just take 144 and divide it by 6 which would look like
144/6 then the answer is 24

5 0

3 years ago

Read 2 more answers

a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

nlexa [21]

Answer:

The standard equation of the parabola is:

$y=-\frac{3}{2}x^2+12x-18$

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

$y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2$

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

$y-6=a\,(x-4)^2\\0-6=a\,(2-4)^2\\-6=a\,4\\a=-\frac{6}{4} =-\frac{3}{2}$

Then the equation of the parabola becomes:

$y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18$

7 0

3 years ago