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Fed [463]
2 years ago
14

A 7th grade homeroom was asked if they would

Mathematics
1 answer:
fiasKO [112]2 years ago
3 0

The probability of choosing a hot dog is 16.7%

<h3>Relative frequency and probability</h3>

Probability is the likelihood or chance that an event will occur

Probability = Expected outcome/Total outcome

From the figure;

Total outcome = 4 + 6 + 2
Total outcome = 12

Since there are 2 hotdogs, hence the probability of choosing a hot dog is given as:

Pr(hot dog) = 2/12

Pr(hot dog) = 0.1667
Hence the probability of choosing a hot dog is 16.7%

Learn more on probability here: brainly.com/question/24756209

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Find k so that the distance from (–1, 1) to (2, k) is 5 units.
velikii [3]

Answer:

k = -3 or 5

Step-by-step explanation:

The given parameters are;

The line extends from points (-1, 1) to point (2, k)

The length of the line = 5 units

The formula for the length, l, of a line given its coordinates can be  found by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Therefore, we have;

5 = \sqrt{\left (k-1 \right )^{2}+\left (2-(-1)  \right )^{2}}

Which, by squaring both sides, gives;

25 = (k - 1)² + (2 - (-1))² = (k - 1)² + (2 + 1)² = (k - 1)² + 3²

25 = (k - 1)² + 3² = k² - 2·k + 1 + 9

25 - 25 = 0 = k² - 2·k + 1 + 9 - 25 = k² - 2·k - 15

0 = k² - 2·k - 15

0 = (k +3) × (k - 5)

Therefore, k = -3 or 5

When k - -3, we have;

\sqrt{\left ((-3)-1 \right )^{2}+\left (2-(-1)  \right )^{2}}= \sqrt{(-4)^2+3^2} = \sqrt{16 + 9}  = \sqrt{25} = 5

When k = 5, we have;

\sqrt{\left (5-1 \right )^{2}+\left (2-(-1)  \right )^{2}}= \sqrt{4^2+3^2} = 5

8 0
3 years ago
If y = 16 when x = 4, find<br> Y when x = 6
Zigmanuir [339]
Y would equal 24 :)
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I just need help solving this problem. Also please don't put the answer into a file because I can't open them. It's also really
dem82 [27]

Answer:

<em>31° </em>

Step-by-step explanation:

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2 years ago
30 greater than 1/2ₓ
anygoal [31]

Answer: True.

Step-by-step explanation:

5 0
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The hypotenuse of a 30°-60°-90°
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