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2 years ago

The parent function f(x) = x3 and its translation, g(x), are shown on the graph.

1 answer:

5 0

The resulting function g(x) = (x-5)^3 + 3 shows a horizontal translation to the right by 5 units and vertical translation up by 3 units

<h3>Translation of functions</h3>

Quadratic functions are functions that has a leading degree of 2.

Given the parent function as shown:

f(x) = x^3

The resulting function g(x) = (x-5)^3 + 3 shows a horizontal translation to the right by 5 units and vertical translation up by 3 units

Learn more on translation here; brainly.com/question/12861087

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Can someone help me please

masya89 [10]

Answer:

A) (3,-8); Reflection

Step-by-step explanation:

The question kind of gave you a hint. Look at how the coordinate point is arranged...

(-y,-x)

That means all positive become negatives and all negatives become positives. This gives you the coordinate of (3,-8).

As for reflection or rotation, the image's coordinates FLIPPED, like how images do in a mirror's reflection.

This means the answer would be A) (3,-8); Reflection.

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3 years ago

Please tell me the final answer to this question and the process. Thanks!

shusha [124]

There are two triangles that are 15cm in height and 10cm in width so you do 15 times 10 which is 150 then divided it by 2 because it a triangle to get 75 then because there is 2 you then multiply it by 2 again and you get 150

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3 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

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3 years ago

Read 2 more answers

Over the course of the school year, you keep track of how much snow falls on a given day and whether it was a snow day. Your dat

Free_Kalibri [48]

Answer:

Probability of the day to be a snow day is 0.34

Step-by-step explanation:

We have the data,

Out of 21 which had less than 3 inches of snow, 5 were snow days.

Out of 8 days which had more than 3 inches of snow, 6 were snow days.

So, we get,

Total number of days = 21 + 8 = 29

Total number of snow days = 5 + 6 = 11

Thus, the probability that the day will be a snow day is $\frac{11}{29}$ i.e. 0.34

Hence, the probability of the day to be a snow day is 0.34.

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3 years ago

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garri49 [273]

Answer:

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Step-by-step explanation:

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3 years ago