The average rate of change of f(x) on the interval [5, 5 + h] is 1
<h3>How to find the
average rate of change of f(x) on the interval [5, 5 + h]?</h3>
The equation of the function is given as:
f(x) = x + 11
The interval is given as: [5, 5 + h]
So, we start by calculating f(5) and f(5 + h)
This gives
f(5) = 5 + 11 = 16
f(5 + h) = 5 + h + 11 = h + 16
The average rate of change of f(x) on the interval [5, 5 + h] is then calculated as:
Rate = [f(5 + h) - f(5)]/[5 + h - 5]
Substitute the known values in the above equation
Rate = (h + 16 - 16)/(5 + h - 5)
Evaluate the sum and the difference
Rate = h/h
This gives
Rate = 1
Hence, the average rate of change of f(x) on the interval [5, 5 + h] is 1
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They've told us the net force already, which is 25 N.
We use this to calculate the unknown force from the right side.
All we do is 135 - 25 = 110 N!
Answer:
<h2>x = 40</h2><h2 />
Step-by-step explanation:
fx=2x-50
Find x when fx=30
30 = 2x - 50
add 50 each side
30 + 50 = 2x - 50 + 50
80 = 2x
x = 80 / 2
x = 40
