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KonstantinChe [14]
2 years ago
10

18+6/-4-16 HELP only d part​

Mathematics
2 answers:
julia-pushkina [17]2 years ago
7 0

Answer:

<h3><em>1/2 </em><u>is the answer</u></h3><h3><u>Step-by-step explanation:</u></h3>

Ivahew [28]2 years ago
3 0

Answer:

\frac{1}{2} is the answer

Step-by-step explanation:

First we need to substitute X and Y with their respective numbers

3\cdot \:6+\frac{6}{-4}-\left(-4\right)^2

Then, following PEMDAS, We just need to simplify

18+\frac{6}{-4} -16

16.5-16=0.5=\frac{1}{2}

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Solve-1/8&lt;34 then graph it
Vlada [557]

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Step-by-step explanation:

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HELP!!! A set of numbers is shown:
Svetllana [295]

Answer:

i am not really sure but i think it is 5,10,15

7 0
3 years ago
HELP ME WITH THIS PLZZZZ​
CaHeK987 [17]
Answer: 17

It’s 17 because they are the same shape and size just are flipped
5 0
2 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
2 years ago
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