CD is called the middle base and is equal to :(AB + EF)/2
CD = <span>(AB + EF)/2
4x = [(x</span>²+10) + (8-x)]/2
8x = x²+10+8-x
8x= x²-x+18
x²-9x+18 = 0
x' = [-b+√(b²-4.a.c)]/2a & x" = [-b-√(b<span>²-4.a.c)]/2a
x'= 6 and x" = 3, So we have2 values of x</span>
Answer:
Check the explanation
Step-by-step explanation:
Ans=
A: For m = 5: P(³≥1) = 1 – P(³=0) = 1 – 0.9973^5 = 0.0134
M = 10: 1 – 0.9973^10 = 0.0267
M = 20: 1 – 0.9973^20 = 0.0526
M = 30: 1 – 0.9973^30 = 0.0779
M = 50: 1 – 0.9973^50 = 0.126
18)
Ans=
Going by the question and the explanation above, we derived sample values of the mean as well as standard deviation in calculating our probability, since that is the necessary value in determining the probability of an out-of-bounds point being plotted. Furthermore, we would know that that value for the possibility would likely be a poor es²ma²on, cas²ng doubt on anycalcula²ons we made using those values
I believe it's 37CM, I had that question on my finals last year.
<h3>Answer is -9</h3>
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Work Shown:
(g°h)(x) is the same as g(h(x))
So, (g°h)(0) = g(h(0))
Effectively h(x) is the input to g(x). Let's first find h(0)
h(x) = x^2+3
h(0) = 0^2+3
h(0) = 3
So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.
Now let's find g(3)
g(x) = -3x
g(3) = -3*3
g(3) = -9
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alternatively, you can plug h(x) algebraically into the g(x) function
g(x) = -3x
g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)
g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3
g( h(x) ) = -3x^2 - 9
Next we can plug in x = 0
g( h(0) ) = -3(0)^2 - 9
g( h(0) ) = -9
we get the same result.
For this case, the first thing to do is to calculate the time you were watching the game.
We have then:
2:00 - 1:45 = 15 minutes
Then, the amount of degrees is given by:
(15/60) * (360) = 90 degrees
Answer:
the minutes hand did turn about:
90 degrees
