The distance of the object from the mirror is 3cm.
To calculate the distance of the object from the mirror, we make use of the mirror formula
<h3>Mirror formula</h3>
- 1/f = (1/u)+(1/v)............ Equation 1
Where:
- f = Focal length of the mirror
- v = image distance
- u = object distance.
Using the real is positive convention,
Given:
Substitute these values into equation 1 and solve for u
- 1/5 = (-1/10)+(1/u)
- 1/5+(1/10) = 1/u
- 1/u = (2+1)/10
- 1/u = 3/10
- u = 10/3
- u = 3.33
- u = 3 cm
Hence, The distance of the object from the mirror is 3cm.
Learn more about mirror formula here: brainly.com/question/26257987
Answer:
P(A or B)=0.6425
Explanation:
To find P(A or B), plug your values for A and B into the equation:
P(A or B)= P(A) + P(B) - P(A and B)
By applying Pythagorean' theorem, the value of tanP is equal to 3/4.
<h3>How to determine the value of tan P?</h3>
Since triangle PQR has right-angle Q and sinR = 4/5, we have:
sinR = Opp/hyp = 4/5
tanP = Opp/Adj = QR/4
Next, we would determine the length of QR by applying Pythagorean' theorem:
PR² = QR² + PQ²
5² = QR² + 4²
25 = QR² + 16
QR² = 25 - 18
QR = √9
QR = 3 units.
For the value of tanP, we have:
tanP = 3/4.
Read more on Pythagorean theorem here: brainly.com/question/23200848
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Answer:
An area that has similar average temperatures and precipitation throughout.
hope this helps.
Answer:
∠C = 159°
∠D = 21°
Explanation:
∠C + ∠D = 180 (1)
∠C = 33 + 6∠D (2)
Substituting (2) to (1):
180 = 33 + 6∠D + ∠D
= 33 + 7∠D
180 - 33 = 7∠D
147 = 7∠D
<u>21 = ∠D</u>
If ∠D = 21,
∠C + 21 = 180
∠C = 180 - 21
<u>∠</u><u>C</u><u> </u><u>=</u><u> </u><u>159</u>
