Find 3 consecutive integers if three times the first integer is two times the third.

1 answer:

8 0

Answer:

4, 5, and 6

Step-by-step explanation:

Three Consecutive integers are x, x+1, x+2

We are given 3 times the first integer is 2 times the third

3x = 2(x+2)

Solve for x

3x = 2x+4

x = 4 (first integer)

so the 3 integers are 4, 5, and 6

You might be interested in

NISA [10]

Answer:

Step-by-step explanation:

The set contains 2 different ranges for 1 domain. In this case, X = 1 returns 5 and -3, meaning it cannot be a function.

4 0

3 years ago

vfiekz [6]

<h3>Answer: Choice B</h3>

The set notation includes all values from -5 to 0, but the domain only includes the integer values

eg: something like -1.2 is in the second set, but it is not in the set {-5,-4,-3,-2,-1}

==========================================================

Further explanation:

Let's go through the answer choices one by one

A. This is false because 0 does not come before -5, but instead -5 is listed first. The order -5,-4,-3,-2,-1,0 is correct meaning that $-5 \le x \le 0$ is the correct order as well.
B. This is true. A value like x = -1.2 is in the set $\left\{x| -5 \le x \le 0\right\}$ since -1.2 is between -5 and 0; but -1.2 is not in the set {-5, -4, -3, -2, -1, 0}. So the distinction is that we're either considering integers only or all real numbers in this interval. To ensure that we only look at integers, the student would have to write $\left\{x| x\in\mathbb{Z}, \ -5 \le x \le 0\right\}$ . The portion $x \in \mathbb{Z}$ means "x is in the set of integers". The Z refers to the German word Zahlen, which translates to "numbers".
C. This is false. The student used the correct inequality signs to indicate x is -5 or larger and also 0 or smaller; basically x is between -5 and 0 inclusive of both endpoints. The "or equal to" portions indicate we are keeping the endpoints and not excluding them.
D. This is false. Writing $-5 \ge x \ge 0$ would not make any sense. This is because that compound inequality breaks down into $-5 \ge x \ \text{ and } \ x \ge 0$ . Try to think of a number that is both smaller than -5 AND also larger than 0. It can't be done. No such number exists.