Two turtles, which are 750 meters apart, start moving toward each other. One turtle travels at an average speed of 1 km/h, and t
2 answers:
The both started at 11.00 a.m then they will meet at 11:15 a.m
We have given that
Two turtles, which are 750 meters apart and the are moving towards each other
average speed of 1 km/h, and the other travels 1 km/h faster
Therefore we have to find When will the turtles meet.
First turtle travels at an average speed of 1 km/h.
Thus; v₁ = 1 km/h
Second turtle travels at an average speed of 1 km/hr faster than the first.
Thus; v₂ = 2 km/h
Since second turtle is moving 2 times faster than the first one, it means the second turtle will cover 2/3 of the total distance while the first will cover 1/3 of the total distance at the point they will meet.
What is the value of 1 kilometre in meter
1 km=1000 meter
So,
Distance covered by turtle 2
Since they both started at 11.00 a.m then they will meet at 11:15 a.m
To learn more about the speed visit:
You might be interested in
Answer:
Step-by-step explanation:
<h2>Algebraic expressions</h2>Difference: should be subtract.
N: should be a number.
Sum: Add
Therefore, the correct answer is 10-N=8+N.
Hope this helps!