Question

Two turtles, which are 750 meters apart, start moving toward each other. One turtle travels at an average speed of 1 km/h, and the other travels 1 km/h faster. When will the turtles meet if they started to move at 11:00 a.m.​
PLS HELP ASAP​

Answer 1

The both started at 11.00 a.m then they will meet at 11:15 a.m

We have given that

Two turtles, which are 750 meters apart and the are moving towards each other

average speed of 1 km/h, and the other travels 1 km/h faster

Therefore we have to find When will the turtles meet.

First turtle travels at an average speed of 1 km/h.

Thus; v₁ = 1 km/h

Second turtle travels at an average speed of 1 km/hr faster than the first.

Thus; v₂ = 2 km/h

Since second turtle is moving 2 times faster than the first one, it means the second turtle will cover 2/3 of the total distance while the first will cover 1/3 of the total distance at the point they will meet.

What is the value of 1 kilometre in meter

1 km=1000 meter

So,

Distance covered by turtle 2

$= 2/3 * 0.750 = 0.5 km$

$Time = distance/speed$

$Time = 0.5/2$

$Time= 0.25 hours \\\\ Time= 15 minutes$

Since they both started at 11.00 a.m then they will meet at 11:15 a.m

To learn more about the speed visit:

brainly.com/question/6672465

Answer 2

Annswer:  11:15 AM

Step-by-step explanation:

Together, the turtles are travelling at 3 kilometers per hour. There is 0.75 kilometers in 750 meters. Divide that by 3. You get 0.25 (1/4). 1/4 of 1 hour is 15 minutes so add that by 11:00 and you get the answer.