3 1/6-2 7/8 what is the snswer

How do you do number 15 and 17? Help please?

vodomira [7]

15)

m = Miguel Indurian titles amount l = Lance Armstrong titles amount

they both won titles to the tour de france, if we add all together, they sum up to 12 for both of them
so.. whatever "m" and "l" are, we could say that m + l = 12

now... Miguel won 2 fewer than Lance, so, whatever "l" is, m = l - 2
thus $\bf \begin{cases}
\boxed{m}=l-2\\\\
m+l=12\\
----------\\
\left( \boxed{l-2} \right)+l=12
\end{cases}$

solve for "l", to see how many Lance won

how many did Miguel win? well, m = l - 2

---------------------------------------------------------------------------------

17)

c = mgs amount in 12oz cup of regular coffee at starbucks
d = mgs amount in 12oz cup of regular decaffeinated coffee at starbucks

we know the regular coffee cup, has 13 times more than the decaf, same 12ouncer

thus whatever "c" and "d" are, we know that c = 13d
both 12ouncers put together, yield 280mgs of caffeine

so, one could say that whatever "c" and "d" are, c + d = 280

thus $\bf \begin{cases}
\boxed{c}=13d\\\\
c+d=280\\
----------\\
\left( \boxed{13d}\right)+d=280
\end{cases}$

solve for "d" to see how much is in the decaffed cup

the regular coffee cup? well c = 13d

8 0

4 years ago

What is does p equal if 8-p = -12 -3p

adelina 88 [10]

Answer:

8-p=-12-3p

8+12-p = -3p

20 = -3p + p

20 = -2p

20/-2 = p

-10 = p

ans. p = -10

...

8 0

3 years ago

Read 2 more answers

For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr

pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables $X_i$ with the following distribution:

$X_i Bin (1,p) = Be(p)$ bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this: