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<u>G</u><u>iven </u><u>:</u><u>-</u>
- A right angled triangle with two sides 10cm and 9cm .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- The value of theta .
<u>Solution</u><u> </u><u>:</u><u>-</u>
At angle theta , 9cm side will be considered as the perpendicular and 10cm side will be hypotenuse . So , as we know that ;
Substituting the respective values,
Simplify,
Take arcsin both sides ,
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>6</u><u>4</u><u>.</u><u>1</u><u>5</u><u>°</u><u> </u><u>.</u><u> </u>
Answer:
Step-by-step explanation:
Given:
19x + 9y = 15
Required:
Rewrite in slope-intercept form, y = mx + b
SOLUTION:
19x + 9y = 15
Subtract 19x from both sides
9y = -19x + 15
Divide both sides by 9
y = -19x/9 + 15/9