Need help ASAP! Directions and problem in the picture ;)
1 answer:
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The equations are in slope intercept form which is
y = mx+b
m is the slope of the equation. slope is rise/ run meaning that if a slope is 2, you can also say 2/1. this means you go up 2 squares and to the right 1 point. if the slope is negative, it looks like a downhill and the line falls left to right. if the slope is positive, it looks like uphill and the line falls right to left.
the x is what the slope is multiplied by but isn’t significant in graphing because it’s always just x
the b represents the y intercept. the y axis is the vertical line on the graph. for example if b = 7, then the line goes through 7 on the graph and basically tells us that (0,7) is a point on the line.
for y= x + 7, the slope is 1. that equation is just saying y= 1x+7 but the one is unnecessary usually because it’s implied that the x means 1x
i attached a picture of the graphed lines
y = mx+b
m is the slope of the equation. slope is rise/ run meaning that if a slope is 2, you can also say 2/1. this means you go up 2 squares and to the right 1 point. if the slope is negative, it looks like a downhill and the line falls left to right. if the slope is positive, it looks like uphill and the line falls right to left.
the x is what the slope is multiplied by but isn’t significant in graphing because it’s always just x
the b represents the y intercept. the y axis is the vertical line on the graph. for example if b = 7, then the line goes through 7 on the graph and basically tells us that (0,7) is a point on the line.
for y= x + 7, the slope is 1. that equation is just saying y= 1x+7 but the one is unnecessary usually because it’s implied that the x means 1x
i attached a picture of the graphed lines
Answer:
is an odd function.
Step-by-step explanation:
We are asked to prove whether is even or odd.
We know that a function is even if
and a function
is odd, when
.
We also know that an even function is symmetric with respect to y-axis and an odd function is symmetric about the origin.
Upon looking at our attachment, we can see that is symmetric with respect to origin, therefore,
is an odd function.
