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Elan Coil [88]
2 years ago
11

Help please, solve prob in the picture

Mathematics
2 answers:
JulsSmile [24]2 years ago
4 0

Answer: The Answer is D

I messed up heh. The person above me is right.

Stolb23 [73]2 years ago
3 0

Answer:

D

Step-by-step explanation:

Dividing a fraction is the same thing as multiplying the dividend by the reciprocal of the divisor.

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Find missing angles and variables
shutvik [7]

Answer:

e= 2x-4  

Step-by-step explanation:

the opposite of e is 2x-4.

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4 years ago
What is the relationship between a conjecture, a theorem, two column proof
Afina-wow [57]
Conjecture
is an educated guess based on known information. Reached by using inductive reasoning
4 0
3 years ago
Find the product of (3x²y²) (4xy³)²
Elena-2011 [213]
First, I would solve the second parenthesis.

(4xy^3)^2

Distribute

(4^2 x^2 y^6)

4 x 4 = 16

Now, combine like terms

3x^2 x 4x^2 = 12x^4

y^2 x y^6 = y^12

So, the answer would be 12x^4 y^12

Hmm actually I'm not sure. I did this about two years ago so I don't really remember sorry if this is really wrong 
5 0
3 years ago
Read 2 more answers
Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
Solve the equation.<br> -3n-4n-17=25<br> n=?
Leno4ka [110]

Answer:

n=-6

Step-by-step explanation:

-3n-4n-17=25

-7n-17=25

-7n=42

n=-6

4 0
3 years ago
Read 2 more answers
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