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mars1129 [50]
3 years ago
13

Im so confused. :/ Anyone?

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0
First one = 9x3=27

Second one 12x9=108

3rd one = 3x4=12
 
Idk what that last one is
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Value of this problem?
Rudik [331]
\frac{4^3\times4^{-1}\times5^{-2}}{4^4\times5^{-3}\times5^0}=\frac{4^{3-1}\times5^{-2}}{4^4\times5^{-3+0}}\\=\frac{4^{2}\times5^{-2}}{4^4\times5^{-3}}=4^{2-4}\times5^{-2-(-3)}\\=4^{-2}\times5^{1}=\frac{5}{4^2}\\=\frac{5}{16}
5 0
2 years ago
You created a scale drawing with the scale 1:8. The client asked you to change it to a scale of 1:10. Will your revised drawing
myrzilka [38]

Answer:

The revised drawing be larger or smaller than your original one

Step-by-step explanation:

The revised drawing be larger or smaller than your original one.

Because   a drawing at a scale of:

  • 1:10 means that the object is 10 times smaller than in real life scale 1:1
  • 1: 8 means that the object is 8 times smaller than in real life scale 1:1

So it means the revised drawing be larger or smaller than your original one

5 0
2 years ago
Read 2 more answers
A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get
julsineya [31]

I have an expression

\sigma = \sqrt{p(1-p)/n}

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

E( (b-p)^2 ) =  (-p)^2(1-p) + (1-p)^2p = p(1-p)

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

\sigma = \sqrt{p(1-p)/n}

Plugging in the numbers,

\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

7 0
3 years ago
Solve the right triangle. Round decimals answers to the nearest tenth.
9966 [12]

Answer:

3^2 + x^2 = 9^2

9 + x^2 = 81

x^2 = 72

x = \sqrt{72\\}, which is about 8.5

Cosine X = 3/9

Cosine X = 1/3

angle x= 70.5

If angle x= 70.5, angle z = 19.5 degrees.

Let me know if this helps!

5 0
2 years ago
Read 2 more answers
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
garik1379 [7]

The complete question is

"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.

0 = 2x^2 – 7x – 9

0 = 4x^ 2 – 3x – 1

The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.

<h3>What is the formula for Discriminant?</h3>

The formula for finding the discriminant is

b^2 - 4ac

The solution contains the term \sqrt{b^2 - 4ac} which will be:

Real and distinct if the discriminant is positive

Real and equal if the discriminant is 0

Non-real and distinct roots if the discriminant is negative

For the quadratic equation 2x^2 - 7x - 9

b^2 - 4ac

= (-7) ^2 - 4( 2) ( -9)\\\\= 49 + 72 = 121

This equation has two real number solutions.

For the quadratic equation 4x^ 2 - 3x- 1

b^2 - 4ac

= (-3) ^2 - 4( 4) ( -1)\\\\= 9 + 16 = 25

This equation will have two real number solutions.

Learn more on discriminant here:

brainly.com/question/1537997

#SPJ1

5 0
1 year ago
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