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astra-53 [7]
4 years ago
9

What is the prime factorization of -800?

Mathematics
1 answer:
ZanzabumX [31]4 years ago
3 0
The answer is 9 I am so smart XD
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100 POINTS??? HELP ME ASAP
Katarina [22]

Answer:

35

Step-by-step explanation:

Double the first equation and get 2x + 2y = 300 (1). Call the second equation 2x + 5y = 405 (2). Calculate (2) - (1) to get 3y = 105, so y = 35.

5 0
3 years ago
Read 2 more answers
What is the comparison between the 3 in 350 and the 3 in 403?
qaws [65]

The 3 in 350 is in the hundreds column and has a value of 300

The 3 in 403 is in the units column and has a value of 3


6 0
3 years ago
If i have a 78 for the year what can I make on my exam to pass
ludmilkaskok [199]
Anything above a 78.
8 0
3 years ago
Find x (2x+1) (5x+5)
mezya [45]

explanation;

Solution for <em>2x+1=5x-5</em> equation

Simplifying

<em>2x + 1 = 5x + -5</em>

Reorder the terms:

<em>1 + 2x = 5x + -5</em>

Reorder the terms:

<em>1 + 2x = -5 + 5x</em>

Solving

<em>1 + 2x = -5 + 5x </em>

Solving for variable<em> 'x'. </em>

Move all terms containing x to the left, all other terms to the right.

Add <em>'-5x'</em> to each side of the equation.

<em>1 + 2x + -5x = -5 + 5x + -5x </em>

Combine like terms: <em>2x + -5x = -3x </em>

<em>1 + -3x = -5 + 5x + -5x </em>

Combine like terms: <em>5x + -5x = 0 </em>

<em>1 + -3x = -5 + 0 </em>

<em>1 + -3x = -5 </em>

Add '-1' to each side of the equation.

<em>1 + -1 + -3x = -5 + -1 </em>

Combine like terms: <em>1 + -1 = 0 </em>

<em>0 + -3x = -5 + -1 </em>

<em>-3x = -5 + -1 </em>

Combine like terms: <em>-5 + -1 = -6 </em>

<em>-3x = -6 </em>

Divide each side by <em>'-3'. </em>

<em>x = 2 </em>

Simplifying

<em>x = 2</em>

8 0
4 years ago
Read 2 more answers
?
yanalaym [24]

Answer:

A=\pi \frac{d^2}{4}

Step-by-step explanation:

The typical equation for the area of a circle is A=\pi r^2. Since the answer choices are in terms of <em>d</em>, the diameter of the circle, you will need to find <em>r</em> in terms of <em>d</em>.

To find <em>r</em> in terms of <em>d</em>, you know that the diameter of a circle is two times its radius. As an equation, this is

d=2r, or solving for <em>r</em>,

r = \frac{d}{2}.

Now that you have an equation for <em>r</em> in terms of <em>d, </em>you can substitute <em>r</em> with \frac{d}{2} from the original equation.

A=\pi r^2

A=\pi (\frac{d}{2})^2

A=\pi \frac{d^2}{4}

4 0
3 years ago
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