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astra-53 [7]
4 years ago
9

What is the prime factorization of -800?

Mathematics
1 answer:
ZanzabumX [31]4 years ago
3 0
The answer is 9 I am so smart XD
You might be interested in
Determine the quotient of 3 over 7 divided by 2 over 3 . 6 over 21 1 over 2 9 over 14 1 and 5 over 9
Naddika [18.5K]

um I dunno because I need points to ask a question sorry

8 1
3 years ago
HELP PLEASE!!!
olga nikolaevna [1]

Answer: A, arithmetic

Step-by-step explanation:

An arithmetic sequence has a constant difference between each term. If she spend 36 dollars each week, the first week would be 36 the second week would be 72, and so on.

8 0
3 years ago
According to the 2017 Corporate Travel Index compiled by Business Travel News, the average daily cost for business travel in the
Gemiola [76]

Answer:

1) X[bar]= $262.60

2) S= $83.55

3) [$57.47; $152.55]

Step-by-step explanation:

Hello!

The objective is to study the average daily cost for business travel in the United States. To test this a sample of the estimated living expenses to 10 international cities was taken. The study variable is X: estimated living costs (including a single room at 4 stars hotel, beverages, breakfast, taxi fares, and incidental costs) on an international city.

Sample data:

n=10

242.87, 260.93, 194.19, 260.86, 355.36, 211.00, 284.08, 139.16, 436.72, 240.87

∑Xi= 2626.04

∑Xi²= 752439.39

1)

The sample mean is calculated by adding all the observed costs and divide it by the sample size:

X[bar]= ∑Xi/n = 2626.04/10= $262.60

2)

To calculate the standard deviation of the sample you have to calculate the sample variance first using the formula:

S²= \frac{1}{n-1}[∑Xi^2-\frac{(∑Xi)^2}{n} ]

S²= \frac{1}{9}[752439.39-\frac{(2626.04)^2}{10} ]

S²= 6981.1979

S= √S² = √6981.1979 = $83.55

3)

To calculate a Confidence Interval for the population standard deviation, you have to first calculate the Confidence Interval for the population variance and then calculate it's square root to obtain the interval for the standard deviation.

This happens because to study a population parameter you need a statistic that follows the following conditions: 1) have known distribution, 2) include the population parameter and it's point estimator, 3) the only incognito of the statistic equation must be the parameter under study. There is no statistic that meets these conditions, but the chi-square statistic meets these conditions and allows you to study the population variance. And this is only possible if the study variable has a normal distribution.

Assuming that the daily living costs have a normal distribution, the formula of the Confidence Interval for the population variance is:

[\frac{(n-1)S^2}{X^2_{(n-1); 1- \alpha/2} } ; \frac{(n-1)S^2}{X^2_{(n-1); \alpha/2} } ]

[\frac{9*6981.1979}{19.023} } ; \frac{9*6981.1979}{2.700} } ]

[$²3302.88; $²23270.66]

So with a confidence level of 95% you'd expect that the confidence interval

[$²3302.88; $²23270.66] will contain the population variance of the estimated living costs (including single room at 4 stars hotel, beverages, breakfast, taxi fares and incidental costs) on an international city.

Now you calculate the square root of the interval:

[√$²3302.88; √$²23270.66]

[$57.47; $152.55]

And at the same level, you'd expect that the interval [$57.47; $152.55] contains the population standard deviation of the estimated living costs (including a single room at 4 stars hotel, beverages, breakfast, taxi fares, and incidental costs) on an international city.

I hope it helps!

6 0
3 years ago
A phone company offers two monthly plans. Plan A costs $25 plus an additional $0.07 for each minute of calls. Plan B costs $16 p
Blizzard [7]

Answer:

1) For 450 minutes of calling the two plans cost the same.

2) The cost when the two plans cost the same is $56.5.

Step-by-step explanation:

The cost of both plans can be modeled by linear functions.

Plan A:

$25 plus an additional $0.07 for each minute of calls.

So, for t minutes of calls, the cost is:

A(t) = 25 + 0.07t

Plan B:

$16 plus an additional $0.09 for each minute of calls.

So, for t minutes of calls, the cost is:

B(t) = 16 + 0.09t

Q1: For what amount of calling do the two plans cost the same?

This is t for which:

A(t) = B(t)

25 + 0.07t = 16 + 0.09t

0.02t = 9

t = \frac{9}{0.02}

t = 450

For 450 minutes of calling the two plans cost the same.

Q2: What is the cost when the two plans cost the same?

This is A(450) or B(450), since they are the same.

B(450) = 16 + 0.09*450 = 56.5

The cost when the two plans cost the same is $56.5.

4 0
4 years ago
90% of the students at Lincoln Middle School attended orientation. If 450 students attended orientation, how many students are a
pentagon [3]

Answer:

495 students are at Lincoln Middle School

Step-by-step explanation:

450/?

450 = 90%

450*90% = 450 * 0.90 =  405

450- 405 = 45  

450+45 = 495

4 0
3 years ago
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